电子邮件屏蔽的正则表达式 [英] Regular expression for email masking

问题描述

我正在尝试编写正则表达式来屏蔽电子邮件地址.下面的示例.

I am trying to write a regular expression to mask an email address. Example below.

输入:[e-mail]

input: [e-mail]

输出:j ******* @ e *********.com

output: j*******@e*********.com

我尝试了以下方法，但似乎无法正常工作.

I have tried the following but I just can't seem to get it working correctly.

regex:(?<=.).(?=[^@]\*?@)

输出:j ******* @ example.en.com

output:j*******@example.en.com

regex:(?<=.).(?=[^@]\*?)(?=[^\.]\*?\.)

output:j ******************.com

output:j******************.com

任何帮助将不胜感激. 演示

Any help would be appreciated. demo

推荐答案

使用各种屏蔽电子邮件解决方案进行更新

• [e-mail]⇒f**@b**.com (当前问题)-s.replaceAll("(?<=.)[^@](?=[^@]*?@)|(?:(?<=@.)|(?!^)\\G(?=[^@]*$)).(?=.*\\.)", "*")(请参见正则表达式演示)

  Update with various masking email solutions

  • [e-mail] ⇒ f**@b**.com (current question) - s.replaceAll("(?<=.)[^@](?=[^@]*?@)|(?:(?<=@.)|(?!^)\\G(?=[^@]*$)).(?=.*\\.)", "*") (see the regex demo)

    [e-mail]⇒f**@b*r.com -s.replaceAll("(?<=.)[^@](?=[^@]*?@)|(?:(?<=@.)|(?!^)\\G(?=[^@]*$)).(?=.*[^@]\\.)", "*")(请参见 regex演示)

    [e-mail]⇒f*o@b*r.com -s.replaceAll("(?<=.)[^@](?=[^@]*?[^@]@)|(?:(?<=@.)|(?!^)\\G(?=[^@]*$)).(?=.*[^@]\\.)", "*")(请参见 regex演示)

    [e-mail]⇒f**@b*****m -s.replaceAll("(?<=.)[^@](?=[^@]*?@)|(?:(?<=@.)|(?!^)\\G(?=[^@]*$)).(?!$)", "*")(请参见 regex演示)

    [e-mail]⇒f*o@b*****m -s.replaceAll("(?<=.)[^@](?=[^@]*[^@]@)|(?:(?<=@.)|(?!^)\\G(?=[^@]*$)).(?!$)", "*")(请参见 regex演示)

    如果您不能使用基于基于代码的解决方案，则可以使用

    In case you can't use a code-based solution, you may use

    s.replaceAll("(?<=.)[^@](?=[^@]*?@)|(?:(?<=@.)|(?!^)\\G(?=[^@]*$)).(?=.*\\.)", "*")
    

    请参见 regex演示

    功能:

    • (?<=.)[^@](?=[^@]*?@)-除@([^@])之外的任何字符，其后跟任何单个字符((?<=.))，后跟任意0个或多个除@之外的字符，直至一个((?=[^@]*?@))
    • |-或
    • (?:(?<=@.)|(?!^)\\G(?=[^@]*$))-匹配字符串中以@开头的位置，并匹配前一个成功匹配项((?!^)\\G)末尾的任何字符((?<=@.))或(|)char @ uo以外的任何0+字符到字符串((?=[^@]*$))的末尾
    • .-任何单个字符
    • (?=.*\\.)-后跟任意0+字符，直到字符串中的最后一个.符号.
    • (?<=.)[^@](?=[^@]*?@) -any char other than @ ([^@]) that is preceded by any single char ((?<=.)) and is followed with any 0 or more chars other than @ up to a @ ((?=[^@]*?@))
    • | - or
    • (?:(?<=@.)|(?!^)\\G(?=[^@]*$)) - match a location in the string that is preceded with @ and any char ((?<=@.)) or (|) the end of the previous successful match ((?!^)\\G) that is followed with any 0+ chars other than @ uo to the end of string ((?=[^@]*$))
    • . - any single char
    • (?=.*\\.) - followed with any 0+ chars up to the last . symbol in the string.

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