正则表达式-匹配句子中每个单词的除第一个字母外的所有字母 [英] Regular Expression - Match all but first letter in each word in sentence

问题描述

我几乎可以在这里找到答案，但是我想念一些东西，希望这里有人可以帮助我.

I've almost got the answer here, but I'm missing something and I hope someone here can help me out.

我需要一个正则表达式，该表达式将匹配句子中每个单词中除第一个字母以外的所有字母.然后，我需要用正确的星号替换匹配的字母.例如，如果我有以下句子:

I need a regular expression that will match all but the first letter in each word in a sentence. Then I need to replace the matched letters with the correct number of asterisks. For example, if I have the following sentence:

There is an enormous apple tree in my backyard.

我需要得到以下结果:

T**** i* a* e******* a**** t*** i* m* b*******.

我设法提出了一个几乎可以做到的表达式:

I have managed to come up with an expression that almost does that:

(?<=(\b[A-Za-z]))([a-z]+)

使用上面的示例语句，该表达式给我:

Using the example sentence above, that expression gives me:

T* i* a* e* a* t* i* m* b*.

如何获得正确数量的星号?

How do I get the right number of asterisks?

谢谢.

推荐答案

尝试一下:

\B[a-z]

\B与\b相反-它匹配没有单词边界的地方-当我们看到另一个字母之后的字母时.

\B is the opposite of \b - it matches where there is no word boundary - when we see a letter that is after another letter.

您的正则表达式将整个单词的尾部-[a-z]+替换为一个星号.您应该一一替换它们.如果您希望它起作用，则应该匹配一个字母，但是check后面有一个单词(这毫无意义，因为您最好检查单个字母(?<=[A-Za-z])[a-z]):

Your regex is replacing the whole tail of the word - [a-z]+, with a single asterisks. You should replace them one by one. If you want it to work, you should match a single letter, but check is has a word behind it (which is a little pointless, since you might as well check for a single letter (?<=[A-Za-z])[a-z]):

(?<=\b[A-Za-z]+)[a-z]

(请注意，最后一个正则表达式后面具有可变长度，大多数正则表达式都没有实现)

(note that the last regex has a variable length lookbehind, which isn't implemented in most regex flavors)

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