在PostgreSQL中如何结合NOT IN和LIKE? [英] In PostgreSQL how to combine NOT IN and LIKE?

问题描述

如何结合NOT IN和LIKE?

让我们假设我们有一个包含一列名称(例如蓝纹奶酪"，"gouda奶酪"之类的名称)的表，而我想选择所有不包含"cheese"，"milk"的名称'，'肉'.

Let's assume we have a table that contains a column of names (something like 'blue cheese', 'gouda cheese' and so on) and I want to select all the names that doesn't contain 'cheese', 'milk', 'meat'.

据我了解，要查找不在字符串数组中的内容，请使用NOT IN并传递字符串

As far as I understand to look for something that is not in an array of strings you use NOT IN and the pass the strings

SELECT names FROM some_table NOT IN('cheese','milk','meat');

但是我如何通过

LIKE '%cheese%'

要吗?

推荐答案

构造LIKE ANY (ARRAY[...])似乎可以满足您的需求；

The construct LIKE ANY (ARRAY[...]) appears to meet your needs;

craig=> SELECT a FROM (
           VALUES ('cheesy'), ('imilk'), ('donut'), ('pie'), ('avocado'), ('meaty')
        ) x(a) 
        WHERE NOT a LIKE ANY (ARRAY['%cheese%','%milk%','%meat%']);

    a    
---------
 cheesy
 donut
 pie
 avocado
(4 rows)

如果要以这种方式使用LIKE，则需要通配符.如果您真的只想平等，可以使用:

You need the wildcard characters if you want to use LIKE this way. If you really just want equality, you can use:

NOT = ANY (...)

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