nsautoreleasepool范围内的return语句 [英] return statement inside nsautoreleasepool scope

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本文介绍了nsautoreleasepool范围内的return语句的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

让我说以下情况:

- (void)someFunction:(id)param {

    NSAutoreleasePool *pool = [[NSAutoreleasePool alloc] init];

    NSObject *objectA = [[NSObject alloc] init];
    [objectA doStuff];  // Don't need to release objectA because of the pool

    if (!someValue) {
        [pool release];   // Doubt here
        return;
    }

    NSObject *objectB = [[NSObject alloc] init];
    [objectB doStuff];  // Don't need to release objectB because of the pool

    [pool release];
}

以这种方式从池块内部返回是否正确?

Is it right to return from inside the pool block in this way?

推荐答案

简短答案:是.

长答案:被嵌套而没有显式释放的池在释放它嵌套的自动释放池(通常是当前线程的顶级自动释放池)时释放.

Long answer: pool that is abandoned without explicit release is released when the autorelease pool in which it nests (usually current thread's top autorelease pool) is released.

顺便说一句,这是错误的:

Btw, this is wrong:

NSObject *objectA = [[NSObject alloc] init];
[objectA doStuff];  // Don't need to release objectA because of the pool

您仍然必须显式释放分配的对象:

You still have to release allocated objects, either explicitly:

NSObject *objectA = [[NSObject alloc] init];
[objectA doStuff];
[objectA release];

或通过将它们添加到自动释放池中:

or by adding them to autorelease pool:


NSObject *objectA = [[[NSObject alloc] init] autorelease];
[objectA doStuff];

这篇关于nsautoreleasepool范围内的return语句的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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