如何快速舍入NSDecimalNumber? [英] How to round an NSDecimalNumber in swift?

问题描述

我在此上找不到任何资源，我一直在尝试各种方法，但是没有任何效果.

I can't find any resources on this, and I've been trying all sorts of stuff, but nothing works.

根据Apple的文档，您将NSDecimalNumber如下舍入:

According to Apple's documentation, you round an NSDecimalNumber like this:

NSDecimalNumber.decimalNumberByRoundingAccordingToBehavior(<#behavior: NSDecimalNumberBehaviors?#>)

它包含一个NSDecimalNumberBehavior，我不确定该如何操作，因为(1)无法将其初始化为变量并且更改了属性，并且(2)根据文档所述的roundingMode()方法没有接受任何参数，但Xcode会为"self"填充参数空间.

It takes in an NSDecimalNumberBehavior, which I'm unsure how to manipulate since it (1) cannot be initiated into a variable and have it's properties changed, and (2) the roundingMode() method according to the documentation doesn't take any parameters, but Xcode fills in a parameter space for "self".

我对此完全迷失了.回到基本问题；如何快速对NSDecimalNumber进行四舍五入?

I'm totally lost on this. Back to the basic question; How can I round an NSDecimalNumber in swift?

预先感谢

推荐答案

您可以这样做

let x = 5
let y = 2
let total = x.decimalNumberByDividingBy(y).decimalNumberByRoundingAccordingToBehavior( NSDecimalNumberHandler(roundingMode: NSRoundingMode.RoundUp, scale: 0, raiseOnExactness: false, raiseOnOverflow: false, raiseOnUnderflow: false, raiseOnDivideByZero: false))   

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