NSKeyedArchiver& NSKeyedUnarchiver/Swift 3.0 [英] NSKeyedArchiver & NSKeyedUnarchiver / Swift 3.0
问题描述
我正在使用NSKeyedArchiver
& NSKeyedUnarchiver
将一些复杂的数据存储在Core-Data
中,以后再在我的应用中检索.
到目前为止,它一直运行良好,但是在迁移之后,Swift 3.0
似乎对我的代码不满意.
I'm using NSKeyedArchiver
& NSKeyedUnarchiver
to store some complex data in Core-Data
and retrieve it later in my app.
This was working perfectly until now, but after migration, Swift 3.0
does not seem to be happy with my code.
我已经在代码中提到了这一点:
var firstArray = [Int](), secondArray = [CGFloat]()
.......
// stores some values in firstArray and also in secondArray.
.......
以下是存储数据的代码:
let masterArray = [firstArray, secondArray] as [Any]
let dataForApp:NSData = NSKeyedArchiver.archivedData(withRootObject: masterArray) as NSData
entityFieldsDico = ["dataForAppArray":dataForApp]
// Use entityFieldsDico to save dataForApp in Core-Data under the key "dataForAppArray".
以下是检索数据的代码:
Here is how the code to retrieve the data looks like:
if let archiveData = dbRecord.value(forKey: "dataForAppArray") {
let archiveArray = NSKeyedUnarchiver.unarchiveObject(with: archiveData as! Data)
firstArray = (archiveArray as! Array)[0] as [Int]
secondArray = (archiveArray as! Array)[1] as [CGFloat]
}
使用代码检索数据时出现问题.它只是在构建时崩溃.
The issue appears whith the code retrieving the data. It simply crashes at build time.
如果我将这两行注释掉:
//firstArray = (archiveArray as! Array)[0] as [Int]
//secondArray = (archiveArray as! Array)[1] as [CGFloat]
该程序有效,除了firstArray& (显然)不可用.
The program works, except for the fact that the data in firstArray & is (obviously) not available.
如果我不将其注释掉,则会崩溃,并显示一条很长的消息,并以下面的内容结尾. (我添加了一些...(点)以缩短消息.)
If I do not comment them out, then I get a crash, with a very long message ending with something like what lies below. (I add some ...(dots) to shorten the message.)
.............
0 swift 0x000000010d71fa3d PrintStackTraceSignalHandler(void*) + 45
1 swift 0x000000010d71f466 SignalHandler(int) + 470
2 libsystem_platform.dylib 0x00007fffa0c5a52a _sigtramp + 26
3 libsystem_platform.dylib 0x0000000000000003 _sigtramp + 1597659891
4 swift 0x000000010b25b4e3 swift::constraints::ConstraintGraphScope::~ConstraintGraphScope() + 899
5 swift 0x000000010b2f45f4 swift::constraints::ConstraintSystem::solveSimplified(llvm::SmallVectorImpl<swift::constraints::Solution>&, swift::FreeTypeVariableBinding) + 24868
...........
Objects-normal/arm64/UP_ViewController.dia -emit-dependencies-path /Users/me/Library/Developer/Xcode/DerivedData/TheApp-dszaazmmftlmwbicuwcwaplkjdfs/Build/Intermediates/TheApp.build/Debug-iphoneos/TheApp.build/Objects-normal/arm64/UP_ViewController.d -emit-reference-dependencies-path /Users/me/Library/Developer/Xcode/DerivedData/TheApp-dszaazmmftlmwbicuwcwaplkjdfs/Build/Intermediates/TheApp.build/Debug-iphoneos/TheApp.build/Objects-normal/arm64/UP_ViewController.swiftdeps -o /Users/me/Library/Developer/Xcode/DerivedData/TheApp-dszaazmmftlmwbicuwcwaplkjdfs/Build/Intermediates/TheApp.build/Debug-iphoneos/TheApp.build/Objects-normal/arm64/UP_ViewController.o -embed-bitcode-marker
1. While type-checking 'computeFunction' at /Users/me/Documents/iOS/TheApp/TheApp/UP_ViewController.swift:184:5
2. While type-checking expression at [/Users/me/Documents/iOS/TheApp/TheApp/UP_ViewController.swift:235:17 - line:235:66] RangeText="firstArray = (archiveArray as! Array)[0] as [Int]"
我有人遇到过这种问题,请告诉我您是如何解决的.
I anyone has experienced this kind of problem, please let me know how you solved it.
推荐答案
您需要将archiveArray
强制转换为Array<Array<Any>>
,然后才能获得包含类型为Any
的值的数组.
You need to cast your archiveArray
to Array<Array<Any>>
then you can get the array of array with contains Any
type value.
您的解决方案是
if let archiveData = dbRecord.value(forKey: "dataForAppArray") {
if let archiveArray = NSKeyedUnarchiver.unarchiveObject(with: archiveData as! Data) as? Array<Array<Any>> {
firstArray = archiveArray[0] as! [Int]
secondArray = archiveArray[1] as! [CGFloat]
}
}
让我们举个例子来了解击球手
Let's take an example for batter understanding
var firstArray = [Int](), secondArray = [CGFloat]()
firstArray.append(1)
firstArray.append(1)
firstArray.append(1)
secondArray.append(1.1)
secondArray.append(1.2)
secondArray.append(1.3)
print(firstArray) //[1, 1, 1]
print(secondArray) //[1.1, 1.2, 1.3]
let masterArray = [firstArray, secondArray] as [Any] //[[1, 1, 1], [1.1, 1.2, 1.3]]
let dataForApp:NSData = NSKeyedArchiver.archivedData(withRootObject: masterArray) as NSData
现在unarchiveObject
返回Any
然后打印输出,以便可以区分两个输出.
Now unarchiveObject
which return Any
then print output so can differentiate both output.
let archiveArray1 = NSKeyedUnarchiver.unarchiveObject(with: dataForApp as Data)
print(archiveArray1!)
输出将为
(
(
1,
1,
1
),
(
"1.1",
"1.2",
"1.3"
)
)
现在将数组转换为Array<Array<Any>>
if let archiveArray = NSKeyedUnarchiver.unarchiveObject(with: dataForApp as Data) as? Array<Array<Any>> {
print(archiveArray)
}
输出将为
[[1, 1, 1], [1.1, 1.2, 1.3]]
希望您能理解我的观点.
Hope you understand my point.
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