指针与整数之间的警告比较 [英] Warning comparison between pointer and integer

问题描述

当我遍历字符指针并检查指针何时到达空终止符时，我会收到警告.

I am getting a warning when I iterate through the character pointer and check when the pointer reaches the null terminator.

 const char* message = "hi";

 //I then loop through the message and I get an error in the below if statement.

 if (*message == "\0") {
  ...//do something
 }

我得到的错误是:

warning: comparison between pointer and integer
      ('int' and 'char *')

我认为message前面的*取消了对消息的引用，所以我得到了message指向何处的值?我不想顺便使用库函数strcmp.

I thought that the * in front of message dereferences message, so I get the value of where message points to? I do not want to use the library function strcmp by the way.

推荐答案

应该是

if (*message == '\0')

在C语言中，单引号分隔单个字符，而双引号分隔字符串.

In C, simple quotes delimit a single character whereas double quotes are for strings.

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