函数调用中的对象引用相同 [英] object reference is same in function calling

问题描述

 -(UserDetail *)functionCheck :(NSString *)str
 {
    UserDetail *d2=[[UserDetail alloc] init];
    NSLog(@"check address::::::> %p",&d2);
    d2.auth_token=str;
    return  d2;

 }

每当我调用functionCheck()函数时，都会打印相同的地址

whenever i am calling functionCheck() function print same address

检查地址::::::> 0xbfffd500

check address::::::> 0xbfffd500

表示分配相同的地址. 返回后如何取消分配UserDetail d2对象.

means it allocate same address. how to deallocate UserDetail d2 object after return.

推荐答案

d2是分配对象的指针，所以您要记录值d2中， 不是其地址 &d2:

d2 is a pointer to the allocated object, so what you want is to log the value of d2, not its address &d2:

NSLog(@"check address::::::> %p", d2); // remove the & !

(&d2是本地堆栈变量的地址，每次调用可能相同.)

(&d2 is the address of the local stack variable, and that may be the same for each call.)

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