从dirent结构中打印off_t文件大小 [英] Printing off_t file size from dirent struct

问题描述

我想要的只是打印文件大小(以字节为单位) 我正在使用

All i want is to print the size of a file in bytes I am using

DIR *d;
struct dirent *dir;
d= opendir(absolute_path);

while((dir= readdir(d))!=NULL){
    printf("%s\t %d\t %u\n",dir->d_name,dir->d_type,(int long long )dir->d_off);
}

打印类型为off_t的d_off是错误的. 对于323,388 bytes文件，它显示1296623584

The printing of the d_off that is type off_t is wrong. For a file of 323,388 bytes it prints 1296623584

我认为强制转换是问题所在.我尝试了很多类型的转换，例如%d，%s，%u，%llu ... 什么是正确的演员表?

I think that the casting is the problem. I tried lots of castings such as %d , %s,%u, %llu... What is the right casting?

用于查找文件大小的正确函数是使用统计结构的lstat().

The right function to use to find filesize is lstat() using a stat struct.

推荐答案

正如@Andrey指出的那样，d_off的值并不总是有用的，甚至不存在.例如，OSX没有它.改用stat呼叫.

As @Andrey points out, the value of d_off is not always useful or even present. OSX does not have it for instance. Use a call to stat instead.

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