错误A2070:无效的指令操作数 [英] error A2070: invalid instruction operands

问题描述

错误在After oop skope中的"mov [esi]，[edi]"行中.我该如何解决这个问题? ;节点删除功能(headptr，nodeToremove)

the error is in AfterLoop skope in the line " mov [esi], [edi]" . how can I resolve this issue? ; The function for node removing (headptr, nodeToremove)

removeNode proc

headPtr = 8
nodeToRemove = headPtr + 4

push ebp
mov ebp, esp
push esi
push edi
push ebx

mov esi, headPtr[ebp]               ; esi = head of list
mov edi, [esi]                  ; edi = second item
cmp esi, nodeToRemove[ebp]              ; head = nodeToRemove?
jne NextNode

mov edi, esi                    ; edi ( = currNode) = head
mov esi, [esi]                  ; new head = head->next
jmp AfterLoop

NextNode:

cmp edi, nodeToRemove[ebp]                  ; currNode = node to remove?
je AfterLoop

mov esi, edi                    ; prev node = currNode
mov edi, [edi]                  ; currNode = currNode->next 
jmp NextNode            

AfterLoop:  

    mov [esi], [edi]            ; error!!! prev->next = curr->next
    pop ebx
    pop edi
    pop esi
    pop ebp
    ret 8
removeNode endp

推荐答案

mem, mem不是操作数的有效组合.使用寄存器作为中介，例如:

mem, mem is not a valid combination of operands. Use a register as an intermediate, e.g.:

mov eax,[edi]
mov [esi],eax

或者，如果可以交换esi和edi，则可以使用movsd:

Alternatively, if you can swap esi and edi you could use movsd:

movsd        ; dword [edi] = dword [esi]; esi += 4; edi += 4

(注意:+= 4为真，前提是方向标记已清除.否则为-= 4.在您的情况下这无关紧要，因为紧接着您是pop esi和edi)

(Note: the += 4 is true assuming that the direction flag is clear. Otherwise it will be -= 4. Shouldn't matter in your case since you pop esi and edi immediatly afterwards).

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