如何获取ContextMenu的所有者(从Silverlight 4工具包)? [英] How to get the Owner of the ContextMenu (from Silverlight 4 toolkit)?

问题描述

当我从Silverlight 4 Toolkit使用ContextMenu时，我想获取ContextMenu实例的Owner，但是它不可用，因为在ContextMenu类中，Owner是一个内部属性.例如，我在边框内放置了一个矩形.当我右键单击一个Rectangle时(然后会出现一个上下文菜单)，我需要更改Rectangle Border的厚度以指示Rectangle是父Grid的当前元素.所以我尝试使用ContextMenu.Loaded事件(通过sender参数获取ContextMenu)，但无法获取该ContextMenu的所有者(即带有边框的Rectangle).我需要那个所有者来增加其边框的粗度.请帮助我找到解决方法.

When I use ContextMenu from Silverlight 4 Toolkit I want to get ContextMenu instance's Owner, but it's not available since in ContextMenu class Owner is an internal property. For example, I have a Rectangle put inside a Border. When I right-click a Rectangle (and a context menu appears) I need to change the Rectangle Border's thickness to indicate that the Rectangle is the current element of the parent Grid, for example. So I try to use ContextMenu.Loaded event where I get the ContextMenu (through the sender parameter), but I can't get the Owner of that ContextMenu (i.e. the Rectangle with its Border). And I need that Owner to make its Border thicker. Please help me find the way to do that.

推荐答案

我发现的唯一收获是从后面的代码中将ContextMenu的DataContext设置为所需的元素.然后通过该DataContext属性解决在上下文菜单上打开的元素.

The only soultion I found was to set ContextMenu's DataContext to the needed element from code behind. And then to address the element on which the context menu was opened throught that DataContext property.

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