使用php从URL获取内容 [英] Get content from a url using php

问题描述

我想从特定的网址获取动态内容:

I want to get the dynamic contents from a particular url:

我已经使用了代码

echo $content=file_get_contents('http://www.punoftheday.com/cgi-bin/arandompun.pl');

我得到以下结果:

document.write('"Bakers have a great knead to make bread."

') document.write('© 1996-2007 Pun of the Day.com
')

我该如何获得字符串?面包师们非常擅长制作面包. 只有第一个document.write中的字符串会更改，其他代码将保持不变

How can i get the string Bakers have a great knead to make bread. Only string inside first document.write will change, other code will remain constant

此致

Pankaj

推荐答案

您正在获取一个JavaScript代码段，该代码段应直接内置在文档中，而不是由脚本查询.里面的代码是JavaScript.

You are fetching a JavaScript snippet that is supposed to be built in directly into the document, not queried by a script. The code inside is JavaScript.

您可以使用正则表达式提取代码，但我建议不要这样做.首先，这样做可能不合法.其次，它们提供的数据格式可以随时更改，从而破坏了脚本.

You could pull out the code using a regular expression, but I would advise against it. First, it's probably not legal to do. Second, the format of the data they serve can change any time, breaking your script.

我认为您应该访问 其RSS feed .您可以以编程方式比JavaScript进行解析.

I think you should take at their RSS feed. You can parse that programmatically way easier than the JavaScript.

查看有关如何执行此操作的问题: 使用PHP解析RSS/Atom提要的最佳方法

Check out this question on how to do that: Best way to parse RSS/Atom feeds with PHP

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