PHP中的三元运算符 [英] The Ternary Operator in PHP
本文介绍了PHP中的三元运算符的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
$chow = 3;
echo ($chow == 1) ? "one" : ($chow == 2) ? "two" : "three";
输出:三个
$chow = 1;
echo ($chow == 1) ? "one" : ($chow == 2) ? "two" : "three";
输出:两个
有人可以解释为什么$ chow = 1而不是"one"时输出为"2"吗?
Can anyone explain why the output is "two" when $chow = 1 instead of "one"?
推荐答案
This is because the ternary operator (?:) is left associative so this is how it's getting evaluated:
((1 == 1) ? "one" : (1 == 2)) ? "two" : "three"
所以1 == 1-> TRUE的意思是:
"one" ? "two" : "three"
和"one"-> TRUE，因此输出为:
And "one" -> TRUE so the output will be:
two
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