基于和/或在搜索概念中的正则表达式中断字符串 [英] Regex break string based on and/or in a search concept

问题描述

我正在尝试创建正则表达式，但遇到了问题.

Hi I am trying to create regex expression and I am running into problems.

基本上这就是我所拥有的:

Basically this is what I have:

(.+?)(and|or)(.+?)

我要寻找的例子:

(user email ends with "@email.com" and user name is "John") or (user email ends with "@domain.com" and user name is "Bob")

我希望得到的预期结果是:

And my expected result that I would like to have is:

(user email ends with "@email.com" and user name is "John")
(user email ends with "@domain.com" and user name is "Bob")

基本上，OR会基于可选的()"进行拆分，因此我可以得到类似的东西

Basically the OR will split based on the "()" which is optional so I can have something like this

user email ends with "@email.com" and user name is "John"

我希望这样:

user email ends with "@email.com"
user name is "John"

如果我必须拥有一个以上的正则表达式，那么上面的最终目标是这样的:

if I have to have more than one regex I'm find with that, The end goal is something like this for the above:

Array
(
    [0] => Array
        (
            [0] => user email ends with "@email.com"
            [1] => user name is "John"
        )

    [1] => Array
        (
            [0] => user email ends with "@domain.com"
            [1] => user name is "Bob"
        )
)

如果是这样

(user email ends with "@email.com" and user name is "John") or ((user email ends with "@domain.com" and user name is "Bob") or (user id is 5))

然后我希望这样的事情

Array
(
    [0] => Array
        (
            [0] => user email ends with "@email.com"
            [1] => user name is "John"
        )

    [1] => Array
        (
            [0] => user email ends with "@domain.com"
            [1] => user name is "Bob"
            [2] => Array
                (
                    [0] => user id is 5
                )
        )
)

任何帮助将不胜感激！

推荐答案

这是一个递归函数，它也使用递归正则表达式，让我们递归！

Here's a recursive function which also uses a recursive regex, let's recurse!!!

$text = '(user email ends with "@email.com" and user name is "John") or ((user email ends with "@domain.com" and user name is "Bob") or (user id is 5))';

print_r(buildtree($text));

function buildtree($input){
    $regex = <<<'regex'
    ~(                      # Group 1
        \(                  # Opening bracket
            (               # Group 2
                (?:         # Non-capturing group
                    [^()]   # Match anything except opening or closing parentheses
                |           # Or
                    (?1)    # Repeat Group 1
                )*          # Repeat the non-capturing group zero or more times
            )               # End of group 2
        \)                  # Closing bracket
    )~x
regex;
// The x modifier is for this nice and fancy spacing/formatting
    $output = [];

    if(preg_match_all($regex, $input, $m)){ // If there is a match
        foreach($m[2] as $expression){  // We loop through it
            $output[] = buildtree($expression); // And build the tree, recursive !!!
        }
        return $output;
    }else{  // If there is no match, we just split
        return preg_split('~\s*(?:or|and)\s*~i', $input);
    }
}

输出:

Array
(
    [0] => Array
        (
            [0] => user email ends with "@email.com"
            [1] => user name is "John"
        )

    [1] => Array
        (
            [0] => Array
                (
                    [0] => user email ends with "@domain.com"
                    [1] => user name is "Bob"
                )

            [1] => Array
                (
                    [0] => user id is 5
                )

        )

)

在线php演示 在线正则表达式演示

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