可以将PHP文件渲染为变量吗? [英] Can you render a PHP file into a variable?

问题描述

如果我有这样的hello.php文件:

If I have a hello.php file like this:

Hello, <?php echo $foo; ?>!

我想在一些php代码中做类似的事情:

I would like to do something like this in some php code:

$text = renderPhpToString('hello.php', array('foo'=>'World'));

最后以

$text == 'Hello, World!'

使用标准PHP 5可以做到吗?显然，我希望使用带有循环等的更复杂的模板.

Is this possible with standard PHP 5? Obviously I want more complex templates with loops and so forth..

推荐答案

您可以使用以下功能:

function renderPhpToString($file, $vars=null)
{
    if (is_array($vars) && !empty($vars)) {
        extract($vars);
    }
    ob_start();
    include $file;
    return ob_get_clean();
}

它使用输出缓冲区控制功能 ob_start() 缓冲以下输出，直到由ob_get_clean().

It uses the output buffer control function ob_start() to buffer the following output until it’s returned by ob_get_clean().

编辑.请确保您验证传递给此函数的数据，以使$vars的file元素不会覆盖传递的$file参数值.

Edit    Make sure that you validate the data passed to this function so that $vars doesn’t has a file element that would override the passed $file argument value.

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