尝试在PHP中获取不带文件名的完整URL [英] Trying to get a full URL without filename in PHP

问题描述

我以为这很简单，但是我似乎找不到具有所要查找内容的$_SERVER数组变量.

I thought this would be simple but I can't seem to find a variable of $_SERVER array that has what I'm looking for.

假设我的网址是http://example.com/subdirectory/index.php，我想获取除文件名-http://example.com/subdirectory/之外的所有内容.

Let's say my url is http://example.com/subdirectory/index.php I want to get all but the filename - http://example.com/subdirectory/.

我知道我可以很容易地通过一些字符串操作来做到这一点，但是我想知道我是否缺少_server数组的变量.我已经尝试了所有的人，看看他们能给什么，但我能得到想要的东西.

I know I could quite easily do this with some string manipulation, but I want to know if there's a var of the _server array that I'm just missing. I've tried all of them to see what they give and I can get anything BUT what I'm looking for.

推荐答案

不会有一个，因为它不是要跟踪的有用属性.如果当前脚本不是index.*以外的其他内容，则不会返回当前脚本的正确URL.

There won't be one because it's not a useful attribute to track. If the current script is something other than index.* then it will not return the correct URL for the current script.

但是，这可能会给您带来想要的东西:

However, this might get you what you want:

echo '//'.$_SERVER['HTTP_HOST'].dirname($_SERVER['PHP_SELF']);

另外，除了安装Firefox的php.net在线手动搜索工具并使用搜索关键字进行设置(通过在URL中键入"php $_server"之类的字词，您可以在$_SERVER全局文档中找到文档)栏)，您还应该知道var_dump()和print_r()可以让您输出任何变量的完整内容，包括数组和对象.这对于调试非常有用.

Also, aside from installing the php.net online manual search tool for Firefox and setting it up with a search keyword (which will let you pull up the documentation on the $_SERVER global by typing something like "php $_server" into your URL bar), you should also know that var_dump() and print_r() lets you output the full contents of any variable, including arrays and objects. This is very useful for debugging.

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