密码:保持登录状态 [英] Codeception: Keep a logged in state

问题描述

我想在大多数测试之前保留或运行登录名.但是如果我尝试将登录代码移到_before之前，因为我没有可用的webguy实例.

I want to keep or run the login before most of my tests. But if I try to move the login code to _before it doesn't work since there is no webguy instance available to me.

在多个测试之间保持会话的最佳方法是什么?到目前为止，这是我的代码，很高兴收到一些帮助.我已经在Google上搜索并检查了文档，但是找不到有关会话内容的任何信息.

What is the best way to keep the session between multiple tests? This is my code so far, would be glad to receive some help. I have googled and checked the documentation but I cannot find anything about session stuff.

<?php
use \WebGuy;

class ProductCest
{

    private $product_id = '1';

    public function _before()
    {
    }

    public function _after()
    {
    }

    // tests
    public function login(WebGuy $I) {
        $I->seeInCurrentUrl('/auth/login');
        $I->fillField("//input[@type='email']", "[e-mail]");
        $I->fillField("//input[@type='password']", "1234");
        $I->click('#signIn .submit');
        $I->wait(500);

        $I->seeInCurrentUrl('/account');
    }

    /**
     * @depends login
     */
    public function chooseProduct(WebGuy $I) {
        $I->wantTo('go to products and choose one');
        $I->amOnPage('/?product=' . $this->client_id);
    }

}

推荐答案

我认为已接受的答案是实现此目标的一种方法，但不是最佳方法.这样，当您只需要共享用户会话时，您将始终必须重现所有登录到系统的步骤.我认为，获取会话cookie并使其通过所需的用户登录测试会更好.为此，您创建一个登录功能，获取cookie，并使您的测试首先取决于登录测试:

I think that the accepted answer is a way of accomplish it, but not the best. Doing that you'll always have to reproduce all the steps to log in into the system, when you only need to share the user session. I think that grabbing the session cookie and pass it through the required user logged tests is better. To do that, you create a login function, get the cookie, and make your tests depends on the login test first:

<?php
use \AcceptanceTester;

class testingCest
{
    private $cookie = null;

    public function _before(AcceptanceTester $I)
    {
    }

    public function _after(AcceptanceTester $I)
    {
    }


    // tests
    public function login(AcceptanceTester $I)
    {
        $I->wantTo('entrar al sistema');
        $I->amOnPage('/');
        $I->seeInCurrentUrl('/admin/login');
        $I->fillField('user','perry');
        $I->fillField('pass','pass-perry');
        $I->click('Login');
        $I->see('You\'re logged!');
        $this->cookie   = $I->grabCookie('your-session-cookie-name');
    }

    /**
     * @depends login
     */
    public function listUsers(AcceptanceTester $I)
    {
        $I->setCookie( 'your-session-cookie-name', $this->cookie );
        $I->amOnPage('/admin/users');
        $I->seeInCurrentUrl('/admin/users/1');
    }

    /**
     * @depends login
     */
    public function listRols(AcceptanceTester $I)
    {
        $I->setCookie( 'your-session-cookie-name', $this->cookie );
        $I->amOnPage('/admin/rols');
        $I->seeInCurrentUrl('/admin/rols/1');
    }
}

这样，如果登录测试失败，则不会获得Cookie，也不会通过其他测试.

That way, if the login test fails, you won't get the cookie, and you won't pass the other tests.

我更喜欢使用此@depends注释，而不是其他答案中建议的@before，因为如果使用@depends，则始终会在测试之前执行代码，而测试只会在登录.

I prefer this @depends annotation instead of the @before proposed in the other answer, because if you use @depends you'll ALWAYS execute the code in the test before, and the tests will be only executed after the login.

下面还有一个答案， https://stackoverflow.com/a/41109855/1168804 可能也有帮助您，因为自撰写此答案以来，Codeception的框架已经在发展.

There exists another answer bellow, https://stackoverflow.com/a/41109855/1168804 that may also help you, as the framework for Codeception has evolved since the writing of this answer.

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