在PHP中将标题转换为url兼容模式的最佳方法? [英] Best way to convert title into url compatible mode in PHP?

问题描述

http://domain.name/1-As Low As 10% Downpayment, Free Golf Membership!!!

上面的网址将报告400 bad request，

如何将此类标题转换为用户友好的好请求?

how to convert such title to user friendly good request?

推荐答案

您可能想改用"slug".而不是使用逐字标题作为URL，您 strtolower() 并用连字符替换所有非字母数字字符，然后删除重复的连字符.如果您想获得额外的荣誉，可以删除停用词也是如此.

You may want to use a "slug" instead. Rather than using the verbatim title as the URL, you strtolower() and replace all non-alphanumeric characters with hyphens, then remove duplicate hyphens. If you feel like extra credit, you can strip out stopwords, too.

因此，首付低至10％，免费的高尔夫会员资格！！！"变成:

So "1-As Low As 10% Downpayment, Free Golf Membership!!!" becomes:

as-low-as-10-downpayment-free-gold-membership

类似这样的东西:

function sluggify($url)
{
    # Prep string with some basic normalization
    $url = strtolower($url);
    $url = strip_tags($url);
    $url = stripslashes($url);
    $url = html_entity_decode($url);

    # Remove quotes (can't, etc.)
    $url = str_replace('\'', '', $url);

    # Replace non-alpha numeric with hyphens
    $match = '/[^a-z0-9]+/';
    $replace = '-';
    $url = preg_replace($match, $replace, $url);

    $url = trim($url, '-');

    return $url;
}

您可以使用更长的正则表达式来缩短它，但是它非常简单.好处是，您可以在数据库上运行查询以匹配标题之前，使用相同的函数来验证查询参数，从而使某人无法将愚蠢的东西粘贴到数据库中.

You could probably shorten it with longer regexps but it's pretty straightforward as-is. The bonus is that you can use the same function to validate the query parameter before you run a query on the database to match the title, so someone can't stick silly things into your database.

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