PHP/正则表达式:用于bbcode [s]或[strike]的简单正则表达式无法正常工作 [英] PHP/Regex: simple regex for bbcode [s] or [strike] fails to work

问题描述

对于一个愚蠢的bbcode解析器，我想在其中添加两个定义，我的原始定义是preg_replace的定义:

For a silly bbcode parser I wanted to add two definitions into one, my original definition was this for preg_replace:

'#\[s\](.*?)\[/s\]#si', '<strike>\\1</strike>'

这可行，我希望用户能够使用[s]或[strike]来以该格式初始化文本，因此我自然地添加了这样的想法:

And this works, I wished for the user to be able to use either [s] or [strike] to initiate text in that format, so I naturally added something like this thinking it would work:

'#\[(s|strike)\](.*?)\[/(s|strike)\]#si', '<strike>\\1</strike>'

不幸的是，[s]和[strike](正确使用)都失败了，而不是您期望的那样: s 和 strike (我的markdown是正确的，可以显示其真实的外观结果，无论其内部是什么，它都显示s或罢工)

Unfortunately that fails, instead of what you would expect, both [s] and [strike] (used properly) make: s and strike (my markdown is correct to show its real looking result, it shows s or strike regardless of what is inside it)

为什么它用标签名称代替内部文本?我在s | str周围加上括号是问题吗?我可能做错了所有..

Why does it replace the inner text with the tag name instead? Is my adding parentheses around the s|strike the problem? I am probably doing this all wrong..

推荐答案

问题是您添加了两个新的正则表达式组，在开始标记中添加了(s|strike)，在结束标记中添加了(s|strike).因此，在生成的代码中，您将得到s或strike.您可以通过使用正确的组号2来解决此问题.

The problem is that you added two new regex groups, (s|strike) in the opening tag and (s|strike) in the closing tag. So inside your resulting code you will get s or strike. You can fix that by simply using the correct group number, 2.

另一种方法是通过在开头添加?:来使新组不引用，但是我想第一个解决方案更容易理解:

Another way would be to make that new groups non-referencing, by adding a ?: to the beginning, but I guess the first solution is easier to understand:

#\[(?:s|strike)\](.*?)\[/(?:s|strike)\]#si

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