如何在Ruby中获得随机数 [英] How to get a random number in Ruby
问题描述
如何生成0
和n
之间的随机数?
How do I generate a random number between 0
and n
?
推荐答案
如果您需要一个随机整数来模拟六边形骰子的卷,则可以使用:
1 + rand(6)
.可以使用2 + rand(6) + rand(6)
模拟掷骰子.
If you needed a random integer to simulate a roll of a six-sided die, you'd use:
1 + rand(6)
. A roll in craps could be simulated with2 + rand(6) + rand(6)
.
最后,如果您只需要一个随机浮点数,只需调用不带任何参数的rand
.
Finally, if you just need a random float, just call rand
with no arguments.
As Marc-André Lafortune mentions in his answer below (go upvote it), Ruby 1.9.2 has its own Random
class (that Marc-André himself helped to debug, hence the 1.9.2 target for that feature).
例如,在此需要进行游戏的游戏中猜10个数字,您可以使用以下命令对其进行初始化:
For instance, in this game where you need to guess 10 numbers, you can initialize them with:
10.times.map{ 20 + Random.rand(11) }
#=> [26, 26, 22, 20, 30, 26, 23, 23, 25, 22]
注意:
-
使用
Random.new.rand(20..30)
(使用Random.new
)通常不是一个好主意,正如他的答案(再次).
Using
Random.new.rand(20..30)
(usingRandom.new
) generally would not be a good idea, as explained in detail (again) by Marc-André Lafortune, in his answer (again).
但是,如果您不使用Random.new
,则 banister (大力地)在注释中指出(并在文档中Random
).只有实例方法可以采用Range
,如生成具有7位数字的随机数所示.
But if you don't use Random.new
, then the class method rand
only takes a max
value, not a Range
, as banister (energetically) points out in the comment (and as documented in the docs for Random
). Only the instance method can take a Range
, as illustrated by generate a random number with 7 digits.
这就是为什么Random.new.rand(20..30)
等于20 + Random.rand(11)
的原因,因为Random.rand(int)
返回一个大于或等于0且小于自变量的随机整数". 20..30
包括30,我需要给出一个0到11之间的随机数,不包括11.
This is why the equivalent of Random.new.rand(20..30)
would be 20 + Random.rand(11)
, since Random.rand(int)
returns "a random integer greater than or equal to zero and less than the argument." 20..30
includes 30, I need to come up with a random number between 0 and 11, excluding 11.
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