生成给定模式的随机文本字符串 [英] Generating random text strings of a given pattern

问题描述

我需要生成特定格式的随机文本字符串.想一些想法，以便我可以用Python编写代码.格式为< 8位数字>< 15字符串>.

I need to generate random text strings of a particular format. Would like some ideas so that I can code it up in Python. The format is <8 digit number><15 character string>.

推荐答案

#!/usr/bin/python

import random
import string

digits = "".join( [random.choice(string.digits) for i in xrange(8)] )
chars = "".join( [random.choice(string.letters) for i in xrange(15)] )
print digits + chars

喜欢比randint()更好地使用random.choice的想法，所以我更新了代码以反映这一点.

liked the idea of using random.choice better than randint() so I've updated the code to reflect that.

注意:这假定需要小写和大写字符.如果仅是小写字母，则将第二个列表理解更改为:

Note: this assumes lowercase and uppercase characters are desired. If lowercase only then change the second list comprehension to read:

chars = "".join( [random.choice(string.letters[:26]) for i in xrange(15)] )

显然，对于大写字母，您只需将其翻转即可，使切片为[26:]，而不是相反.

Obviously for uppercase only you can just flip that around so the slice is [26:] instead of the other way around.

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