使用choice()和randint()从2个范围中获取1个数字 [英] Getting 1 number from 2 ranges with choice() and randint()

问题描述

我有一个代码块

import random as r
value = r.choice(r.randint(10, 30), r.randint(50, 100))
print (value)

为什么会给我以下错误，我该如何解决?

Why does it give me the following error, and how should I fix it?

TypeError: choice() takes 2 positional arguments but 3 were given 

推荐答案

choice可以选择一系列项目，而不是varargs.将参数包装成匿名tuple或list，它将起作用，并进行以下更改:

choice takes a sequence of items to choose from, not varargs. Wrap the arguments to make an anonymous tuple or list and it'll work, changing:

value = r.choice(r.randint(10, 30), r.randint(50, 100))

到以下任何一个

value = r.choice((r.randint(10, 30), r.randint(50, 100)))  # Tuple
value = r.choice([r.randint(10, 30), r.randint(50, 100)])  # List

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