Quickblox iOS:在视频聊天中连接2个用户而无需发起呼叫 [英] Quickblox iOS: Connecting 2 users in video chat without initiating a call
问题描述
我有一个视频聊天要求，其中我必须通过视频聊天连接2个(有点相关)用户.我找不到要调用的必要api，因此出现了问题.
I have a video chat requirement wherein I have to connect 2 (somewhat related) users through video chat. I am not finding necessary api to call, hence the question.
我基本上是在遵循本教程，但似乎并没有全部内容我需要.我不需要显式的呼叫此用户"功能.用户永远不会看到整个用户列表.
I am basically following this tutorial but it seems it doesn't have everything I need. I do not need explicit "call to this user" sort of function. The user never gets to see entire user list.
结果，我想知道是否可以让X个用户拨打电话，再让X个用户等待接听该电话.
As a result, I wonder if I could have X number of users calling and another X number of users waiting to accept that call.
总结:
我只想根据某些特征(例如他们的注册标签)来连接用户.对于任何用户A，可以有一个以上的用户具有与A相似的标签-因此，所有这些用户都是用户A的潜在视频聊天用户.
I just want to connect users based on some traits (like their registered tags). For any user A, there can be more than one users having similar tags as A - so all of them are prospect video chat users for user A.
我需要选择其中之一(可能会随机播放)，并在其中流式传输A的视频/音频.
I need to pick one of them (random may work) and stream A's video / audio among them.
我必须做什么?这是部分清单，但我不知道我说的对不对.
What all things do I have to do? Here is partial list but I don't know I am right at the end.
1-致电[QBAuth createSessionWithDelegate:self]
2-在产生的会话中，调用[QBUsers logInWithUserLogin]
2 - From the resulting session, call [QBUsers logInWithUserLogin]
3-在产生的会话中，调用[[QBChat instance] loginWithUser:user]
3 - From the resulting session, call [[QBChat instance] loginWithUser:user]
4-从生成的chatDidLogin委托中，调用什么?
4 - From the resulting chatDidLogin delegate, call what?
应该进入某个聊天室，还是使用 chatRoomDidChangeOnlineUsers 使用某些代码?我不知道.
Should it be entering some chat room, or use of some code using chatRoomDidChangeOnlineUsers? I don't know.
请帮助我以最简单的方式调用事情，简而言之，修改上面的1-2-3-4.
Please help me with the minimal required sequence of things to call, in short, modify 1-2-3-4 above.
更新为何无法发起呼叫的原因:
这是因为由于聊天是非自愿的，因此通话可能会发生冲突.如果我使用calluser api，则每个人最终都会调用.等待接听电话也是如此.我无法想到一种公平的策略，在该策略中，系统不会因呼叫请求而变得不知所措，也不会因每个人都在等待而保持沉默.
This is because since chat is involuntary, calls may collide. If I use calluser api, everyone would end up calling. Likewise is true for waiting to accept a call. I am unable to think of a fair strategy wherein the system does not get overwhelmed with call requests, or silent due to everyone keeps waiting.
换句话说，我支持以下解决方案:每个用户都可以选择一个随机的人呼叫，但不介意是否有人呼叫他，他应该能够优雅地处理它.
In other words I am for the solution wherein every user can pick a random person to call, but does not mind if someone else calls him, and he should be able to handle it gracefully.
推荐答案
首先，您应该注册新用户并向他发送一些标签.为此，您必须:
First of all you should register new user and send him some tag. To do this you have to:
1)创建一个会话
[QBAuth createSessionWithDelegate:self]
[QBAuth createSessionWithDelegate:self]
2)注册新用户并为其设置一些标签:
2) Register new User and set him some tag:
QBUUser *user = [QBUUser user];
user.login = @"someuser";
user.password = @"somepass";
user.tags = @[@"Tag1"];
3)使用相同的标签创建更多用户
3) Create more users with the same tag
接下来，为了与某个用户进行通话，您必须随机获得它.这是要求所有具有特定标签的用户的请求:
Next, in order to have a call with some user you have to randomly get it. Here is a request to get all the users with particular tag:
[QBUsers usersWithTags:@[@"Tag1"] delegate:self];
您将获得所有使用此标签的用户.接下来-随机选择其中之一
you will get all users with this tag. Next - choose one of them randomly
最后，与该用户进行视频通话
Finally, make a video call to this user
使用用户"样本来学习如何使用用户"模块 http://quickblox.com/developers/SimpleSample-users-ios
Use Users sample to learn how to work with Users module http://quickblox.com/developers/SimpleSample-users-ios
顺便说一句:QuickBlox发布了带有新块API的SDK 2.0-您可以尝试 http:///quickblox.com/developers/IOS#iOS_SDK_Transition_guide_from_version_1.9_to_2.0
btw: QuickBlox released SDK 2.0 with new blocks API - you can try it http://quickblox.com/developers/IOS#iOS_SDK_Transition_guide_from_version_1.9_to_2.0
这篇关于Quickblox iOS:在视频聊天中连接2个用户而无需发起呼叫的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
