pydub append-引擎盖下行为的澄清 [英] pydub append - clarification of under the hood behaviour

问题描述

我一直在使用pydub将短声音文件连接成更大的声音文件.基本代码如下:

I've been using pydub to concatenate short sound files into a larger sound file. The basic code for this looks like this:

def permuPhrase(iterations, joins): # Builds a single phrase and does various permutations of it
sampleSet = entryMatcher()
sampleSet.inputVars()
sampleSet.match()
concat = 0
if len(sampleSet.results) != 0:
    for x in range(iterations):
        for i in range(joins):
            rand = rn.randint(0, len(sampleSet.results)- 1)
            choice = str(sampleSet[rand])
            concat += (AudioSegment.from_wav(source+choice+affix))
        numIter = str(x) # convert parent for loop to string for naming .wav files.
        concat.export(newDir+numIter+affix, format="wav") # export
else:
    print("No samples matched")

我的问题是这个.在API中，它指出默认情况下存在100ms淡入淡出.但是，下面给出的示例建议，如果使用+运算符来连接样本，则不使用交叉淡入淡出.我想知道是否有人可以澄清这一点?我链接了API，因为无法复制示例.它位于AudioSegment(...).append()下.

My question is this. In the API it states there is by default an 100ms crossfade. However, the example given below suggests that if you use a + operator to concatenate samples it uses no crossfade. I was wondering if anyone can clarify this? I've linked the API as copying the example was not readable. It's under AudioSegment(...).append().

AudioSegment(...).append()

返回一个新的AudioSegment，该新的AudioSegment通过附加另一个 AudioSegment到此(即，将其添加到末尾)，可以选择 使用交叉淡入淡出.在以下情况下在内部使用AudioSegment(…).append() 与+运算符一起添加AudioSegment对象.

AudioSegment(…).append()

Returns a new AudioSegment, created by appending another AudioSegment to this one (i.e., adding it to the end), Optionally using a crossfade. AudioSegment(…).append() is used internally when adding AudioSegment objects together with the + operator.

默认情况下，使用100毫秒(0.1秒)淡入淡出效果来消除爆裂声 和裂纹.

By default a 100ms (0.1 second) crossfade is used to eliminate pops and crackles.

from pydub import AudioSegment
sound1 = AudioSegment.from_file("sound1.wav")
sound2 =AudioSegment.from_file("sound2.wav")

# default 100 ms crossfade
combined = sound1.append(sound2)

# 5000 ms crossfade
combined_with_5_sec_crossfade = sound1.append(sound2, crossfade=5000)

# no crossfade
no_crossfade1 = sound1.append(sound2, crossfade=0)

# no crossfade
no_crossfade2 = sound1 + sound2

支持的关键字参数:

• crossfade |例如:3000 |默认值:100(整个持续时间AudioSegment)指定时，方法以X为单位返回帧数 AudioSegment
的毫秒数

• crossfade | example: 3000 | default: 100 (entire duration of AudioSegment) When specified, method returns number of frames in X milliseconds of the AudioSegment

推荐答案

我可以确认使用+运算符进行的级联不会应用任何交叉淡入淡出(实际上是

I can confirm that concatenation using the + operator doesn’t apply any cross fade (and in fact calls the append method with crossfade=0)

做出设计决定的原因是允许使用sum()和reduce()以及其他类似方法将一堆块放回去而不会改变总持续时间(由于交叉淡入淡出的重叠)

The reason for that design decision was to allow using sum() and reduce() and other similar methods to put a bunch of chunks back together without altering the total duration (due to the crossfade overlaps)

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