为什么sys.exit()引起回溯? [英] Why is sys.exit() causing a traceback?

问题描述

根据 如何从Python退出而无需追溯? ，在其中调用sys.exit() Python脚本应无提示地退出，而不会产生回溯.

According to How to exit from Python without traceback?, calling sys.exit() in a Python script should exit silently without a traceback.

import sys
sys.exit(0)

但是，当我使用python -i "exit.py"在Windows 7上从命令行启动脚本时，(或从Notepad ++ )，则会显示对 SystemExit 异常的回溯./p>

However, when I launch my script from the command line on Windows 7 with python -i "exit.py", (or from Notepad++), a traceback for a SystemExit exception is displayed.

U:\>python -i "exit.py"
Traceback (most recent call last):
  File "exit.py", line 2, in <module>
    sys.exit(0)
SystemExit: 0
>>>

为什么sys.exit()从Windows命令行运行时显示回溯?

Why is sys.exit() displaying a traceback when run from the Windows command line?

(供参考，我在Windows 7上使用Python 3.6.4)

(For reference, I am using Python 3.6.4 on Windows 7)

推荐答案

您正在使用-i标志运行Python. -i禁止对SystemExit进行通常的特殊处理sys.exit引发；由于抑制了特殊处理，因此Python将执行常规的异常处理，该异常处理将显示回溯.

You're running Python with the -i flag. -i suppresses the usual special handling of the SystemExit exception sys.exit raises; since the special handling is suppressed, Python performs the normal exception handling, which prints a traceback.

可以说，-i应该只禁止特殊处理的退出"部分，而不引起回溯打印.您可以提出错误报告；我没有看到任何现有的相关报告.

Arguably, -i should only suppress the "exit" part of the special handling, and not cause a traceback to be printed. You could raise a bug report; I didn't see any existing, related reports.

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