如何正确读取Flux< DataBuffer>.并将其转换为单个inputStream [英] How to correctly read Flux<DataBuffer> and convert it to a single inputStream

问题描述

我正在为春季启动应用程序使用WebClient和自定义BodyExtractor类

WebClient webLCient = WebClient.create();
webClient.get()
   .uri(url, params)
   .accept(MediaType.APPLICATION.XML)
   .exchange()
   .flatMap(response -> {
     return response.body(new BodyExtractor());
   })

BodyExtractor.java

@Override
public Mono<T> extract(ClientHttpResponse response, BodyExtractor.Context context) {
  Flux<DataBuffer> body = response.getBody();
  body.map(dataBuffer -> {
    try {
      JaxBContext jc = JaxBContext.newInstance(SomeClass.class);
      Unmarshaller unmarshaller = jc.createUnmarshaller();

      return (T) unmarshaller.unmarshal(dataBuffer.asInputStream())
    } catch(Exception e){
       return null;
    }
  }).next();
}

以上代码适用于较小的有效负载，但不适用于较大的有效负载，我认为这是因为我仅使用next读取单个通量值，并且不确定如何组合和读取所有dataBuffer./p>

我是电抗器的新手，所以我对通量/单声道不了解很多窍门.

解决方案

我能够通过使用Flux#collect和SequenceInputStream

使其工作

@Override
public Mono<T> extract(ClientHttpResponse response, BodyExtractor.Context context) {
  Flux<DataBuffer> body = response.getBody();
  return body.collect(InputStreamCollector::new, (t, dataBuffer)-> t.collectInputStream(dataBuffer.asInputStream))
    .map(inputStream -> {
      try {
        JaxBContext jc = JaxBContext.newInstance(SomeClass.class);
        Unmarshaller unmarshaller = jc.createUnmarshaller();

        return (T) unmarshaller.unmarshal(inputStream);
      } catch(Exception e){
        return null;
      }
  }).next();
}

InputStreamCollector.java

public class InputStreamCollector {
  private InputStream is;

  public void collectInputStream(InputStream is) {
    if (this.is == null) this.is = is;
    this.is = new SequenceInputStream(this.is, is);
  }

  public InputStream getInputStream() {
    return this.is;
  }
}

I'm using WebClient and custom BodyExtractorclass for my spring-boot application

WebClient webLCient = WebClient.create();
webClient.get()
   .uri(url, params)
   .accept(MediaType.APPLICATION.XML)
   .exchange()
   .flatMap(response -> {
     return response.body(new BodyExtractor());
   })

BodyExtractor.java

@Override
public Mono<T> extract(ClientHttpResponse response, BodyExtractor.Context context) {
  Flux<DataBuffer> body = response.getBody();
  body.map(dataBuffer -> {
    try {
      JaxBContext jc = JaxBContext.newInstance(SomeClass.class);
      Unmarshaller unmarshaller = jc.createUnmarshaller();

      return (T) unmarshaller.unmarshal(dataBuffer.asInputStream())
    } catch(Exception e){
       return null;
    }
  }).next();
}

Above code works with small payload but not on a large payload, I think it's because I'm only reading a single flux value with next and I'm not sure how to combine and read all dataBuffer.

I'm new to reactor, so I don't know a lot of tricks with flux/mono.

解决方案

I was able to make it work by using Flux#collect and SequenceInputStream

@Override
public Mono<T> extract(ClientHttpResponse response, BodyExtractor.Context context) {
  Flux<DataBuffer> body = response.getBody();
  return body.collect(InputStreamCollector::new, (t, dataBuffer)-> t.collectInputStream(dataBuffer.asInputStream))
    .map(inputStream -> {
      try {
        JaxBContext jc = JaxBContext.newInstance(SomeClass.class);
        Unmarshaller unmarshaller = jc.createUnmarshaller();

        return (T) unmarshaller.unmarshal(inputStream);
      } catch(Exception e){
        return null;
      }
  }).next();
}

InputStreamCollector.java

public class InputStreamCollector {
  private InputStream is;

  public void collectInputStream(InputStream is) {
    if (this.is == null) this.is = is;
    this.is = new SequenceInputStream(this.is, is);
  }

  public InputStream getInputStream() {
    return this.is;
  }
}

这篇关于如何正确读取Flux< DataBuffer>.并将其转换为单个inputStream的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！