Ruby Timeout :: timeout不会引发异常，并且不会返回记录的内容 [英] Ruby Timeout::timeout doesn't fire Exception and doesn't return what documented

问题描述

我有这段代码:

begin
  complete_results = Timeout.timeout(4) do      
    results = platform.search(artist, album_name)
  end
rescue Timeout::Error
  puts 'Print me something please'
end 

然后我启动包含此代码的方法，好了，这是堆栈跟踪的开始:

I then launch the method containing this code, and well, here is the beginning of a stack trace:

Exception message :  execution expired
Exception backtrace :  /***/****/.rvm/rubies/ruby-1.8.7-p302/lib/ruby/1.8/timeout.rb:64:i

所以我天真的认为我的通话超时了.但是永远不会打印请给我打印一些东西"，并且complete_results假定是超时状态返回值(如文档中所述，为true或false)，绝对不是布尔值.

So i naively thinks that my call timeouted. But 'Print me something please' is never printed and complete_results wich is suppose to be the timeout status return value (either true or false, as mentionned in the documentation), is definitively not a boolean.

我做错什么了吗?

推荐答案

您的代码正确

require 'timeout'
begin
  complete_results = Timeout.timeout(1) do      
   sleep(2)
  end
rescue Timeout::Error
  puts 'Print me something please'
end

打印出请给我打印点东西".

does print out "print me something please".

尝试上面的基本代码.如果可行，则您在platform.search中遇到问题.

Try the basic code as above. If that works, you have an issue in platform.search.

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