是否可以使用结构化数据查看人员? [英] It is possible to review a Person with structured data?

问题描述

我查看了以人为中心的数据.

I have review data centered around people.

我想用结构化数据来代表这些评论.

I would like to represent these reviews with structured data.

类似这样的东西:( 从这里 )

Something like this: (from here)

这是我尝试的方法:(这是Google图书示例的变体

This is what I tried: (It's a variation of the Google's Book example here)

<div itemscope itemtype="http://schema.org/Person">
  <h2>
    <span itemprop="honorificPrefix">Dr</span>
    <span itemprop="name">Joe Smith</span>
  </h2>
  <h3 itemprop="jobTitle">Doctor</h3>
  <div itemprop="description">Extra super Doctor</div>
  <div itemprop="aggregateRating" itemscope itemtype="http://schema.org/AggregateRating">
    <div>Doctor rating:
      <span itemprop="ratingValue">88</span> out of 
      <span itemprop="bestRating">100</span> with
      <span itemprop="ratingCount">20</span> ratings
    </div>
  </div>
</div>

现在，当我在 Google的测试工具中测试此代码时，我得到错误:

Now when I test this code in Google's testing tool, I get the error:

Google无法识别对象的属性gregationRating 类型的人.

The property aggregateRating is not recognized by Google for an object of type Person.

那么这是否意味着没有办法对具有结构化数据的人进行评分?

So does this mean that there is there no way to rate people with structured data?

推荐答案

仅 aggregateRating属性为CreativeWork/Offer/Organization/Place/Product定义，但没有为Person定义.

The aggregateRating property is only defined for CreativeWork/Offer/Organization/Place/Product, but not for Person.

替代品:

• AggregateRating 定义了

• AggregateRating defines the itemReviewed property, which expects a Thing as value, so it can be used with Person:

AggregateRating→itemReviewed→Person

您可能还想考虑是否真的是在这里获得评分的人，而不是该人提供的东西(即像体检这样的服务):

You might also want to consider if it’s really the person that gets rated here, and not something that this person offers (i.e., a service like a medical examination):

Person→ makesOffer →Offer
Offer→ aggregateRating →AggregateRating

Person → makesOffer → Offer
Offer → aggregateRating → AggregateRating

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