在每个delay_job抽佣作业中获取额外的rufus-scheduler线程:工作 [英] Getting extra rufus-scheduler thread with each delayed_job rake jobs:work

问题描述

我正试图使用​​rufus-scheduler检查每一分钟，以查看是否 有准备好要放置在delay_job队列中的作业.

Am trying to use rufus-scheduler to check every minute or so to see if there are jobs ready to be placed in the delayed_job queue.

在#{RAILS_ROOT}/config/initializers中具有一个初始化脚本，该脚本可以 启动调度程序.不幸的是，耙工作:工作也运行 Rails初始化过程，因此每个都可以开始 工作:工作已经开始.

Have an initializer script in #{RAILS_ROOT}/config/initializers that starts the scheduler. Unfortunately the rake jobs:work also runs the rails initialization process so another gets started for each jobs:work started.

如何防止这种情况?

运行红宝石1.8.6.26，导轨2.3.5，dj 1.8.5，rufus-scheduler 2.0.6于 XP pro sp3

Running ruby 1.8.6.26, rails 2.3.5, dj 1.8.5, rufus-scheduler 2.0.6 on XP pro sp3

推荐答案

在初始化程序中，找到一种方法，如果通过Rake调用rails初始化过程，则不运行计划.

In your initializer, find a way not to run the schedule if the rails initialization process is invoked via Rake.

可以肯定的是，这是一种更加卑鄙的方式，但是您可以做到

For sure there is a more railsy way, but you could do

  unless defined?(Rake)
    # do the scheduling...
  end

如果定义了恒定的Rake(对于Rake任务，则不定义)，则不会调用执行调度"块.

The block 'do the scheduling' won't get called if the constant Rake is defined (for a Rake task it is defined).

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