如何在标题栏中找到最长的重复序列? [英] How to find the longest duplicate sequence in a tibble column?
问题描述
我更新了我的问题,因为我需要在输出三角栏中再增加一列.
I updated my question because I need one more column to my output tible.
我有以下提示:
library(tibble)
my_tbl <- tribble(
~year, ~event_id, ~winner_id,
2011, "A", 4322,
2012, "A", 4322,
2013, "A", 4322,
2014, "A", 5478,
2015, "A", 4322,
2011, "B", 4322,
2012, "B", 7893,
2013, "B", 7893,
2014, "B", 2365,
2015, "B", 3407,
2011, "C", 5556,
2012, "C", 5556,
2013, "C", 1238,
2014, "C", 2391,
2015, "C", 2391,
2011, "D", 4219,
2012, "D", 7623,
2013, "D", 8003,
2014, "D", 2851,
2015, "D", 0418
)
我想按事件ID找出连续最多的胜利.我要寻找的结果看起来像这样:
I would like to find out the most wins in a row by event id. The result I'm looking for would look like this:
results_summary_tbl<-tribble( 〜event_id,〜most_wins_in_a_row,〜winners数,〜winners,〜years, "A",3,1,"4322","4322 =(2011,2012,2013)", "C",2,2,"5556,2391","5556 =(2011,2012),2391 =(2014,2015)", "B",2,1,"7893","7893 =(2012,2013)", "D",1、5,"4219、7623、8003、2851、0418","4219 =(2011),7623 =(2012),8003 =(2013),2851 =(2014),0418 =(2015) " )
results_summary_tbl <- tribble( ~event_id, ~most_wins_in_a_row, ~number_of_winners, ~winners, ~years, "A", 3, 1, "4322", "4322 = (2011, 2012, 2013)", "C", 2, 2, "5556 , 2391", "5556 = (2011, 2012), 2391 = (2014, 2015)", "B", 2, 1, "7893", "7893 = (2012, 2013)", "D", 1, 5, "4219 , 7623 , 8003 , 2851 , 0418", "4219 = (2011), 7623 = (2012), 8003 = (2013), 2851 = (2014), 0418 = (2015)" )
谢谢
推荐答案
一个dplyr
选项可能是:
my_tbl %>%
add_count(event_id, rleid = cumsum(winner_id != lag(winner_id, default = first(winner_id)))) %>%
group_by(event_id) %>%
summarise(most_wins_in_a_row = max(n),
number_of_winners = n_distinct(winner_id[n == max(n)]),
winners = paste0(unique(winner_id[n == max(n)]), collapse = ","))
event_id most_wins_in_a_row number_of_winners winners
<chr> <int> <int> <chr>
1 A 3 1 4322
2 B 2 1 7893
3 C 2 2 5556,2391
4 D 1 5 4219,7623,8003,2851,418
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