C语言压缩程序 [英] Compression Program in C

问题描述

我想压缩一系列字符.例如，如果我输入

I want to compress a series of characters. For example if i type

输入:FFFFFBBBBBBBBBCCBBBAABBGGGGGSSS(27 x 8位= 216位) 输出:F5B7C2B3A2B2G5S3(14 x 8位= 112位)

Input : FFFFFBBBBBBBCCBBBAABBGGGGGSSS (27 x 8 bits = 216 bits) Output: F5B7C2B3A2B2G5S3 (14 x 8 bits = 112bits)

到目前为止，这就是我所拥有的，我可以算出数组中的字符数.但是最重​​要的任务是按照相同的顺序对其进行计数.我似乎无法弄清楚:( 就在几周前，我就盯着C做我，我对数组，指针，ASCII值有了解 但无论如何似乎都无法按顺序计算这些字符.香港专业教育学院尝试一切.这种方法不好，但是最接近我.

So far this is what i have, i can count the number of Characters in the Array. But the most important task is to count them in the same sequence. I can't seem to figure that out :( Ive stared doing C just a few weeks back, i have knowledge on Array, pointers, ASCII value but in any case can't seem to count these characters in a sequence. Ive try a bit of everything. This approach is no good but it the closest i came to it.

#include <stdio.h>
#include <conio.h>

int main()
{

 int charcnt=0,dotcnt=0,commacnt=0,blankcnt=0,i, countA, countB;
 char str[125];



 printf("*****String Manipulations*****\n\n");
 printf("Enter a string\n\n");

 scanf("%[^'\n']s",str);


 printf("\n\nEntered String is \" %s \" \n",str);


 for(i=0;str[i]!='\0';i++)
 {

 // COUNTING EXCEPTION CHARS                         
 if(str[i]==' ')
    blankcnt++;

 if(str[i]=='.')
    dotcnt++;

 if(str[i]==',')
    commacnt++;

 if (str[i]=='A' || str[i]=='a')

  countA++;

      if (str[i]=='B' || str[i]=='b')

  countA++;

 }

 //PRINT RESULT OF COUNT
 charcnt=i;
 printf("\n\nTotal Characters : %d",charcnt);
 printf("\nTotal Blanks     : %d",blankcnt);
 printf("\nTotal Full stops : %d",dotcnt);
 printf("\nTotal Commas     : %d\n\n",commacnt);
 printf("A%d\n", countA);

 }

推荐答案

这是我为此分配工作制定的解决方案-此函数用于压缩字符串.如果仍然有问题，希望对您有所帮助.

Here is the solution I've worked out for this assignment- This function was used to do the compression of the string. Hope it help if any still having problem.

    #include <stdio.h>

extern compression_function(char arr[1000])

{
   char current_char;
   int count, i,j=0,t=0,G=0,H=0, char_size=0;
   int original_length=0,com_number_length=0,compressed_length=0;
   int index=0;

    FILE* outputfile;
    FILE* processing;

   outputfile= fopen("C:\\Users\\Desktop\\output.txt","w");
   processing= fopen("C:\\Users\\Desktop\\processing.txt","w");

   if(outputfile == '\0' )
{ 
                printf("Cannot Write To File!\n");

                }        


current_char = arr[0]; 
count = 1; 
i = 0; 

printf("\n\nOUTPUT: ");
//USING A WHILE LOOP
while (arr[i] != '\0') 
{ 
//'i' WILL BE INCREMENTED TO CHECK ALL THE CHAR IN THE ARRAY      

i++;

// CHECK IF THE CURENT CHAR IS THE SAME AS THE LAST ONE        
if( arr[i] == current_char )
{
count++; 
}

//ELSE IF NO MORE CHAR IS SIMILAR, IT WILL PRINT THE COUNT RESULT RIGHT AWAY    
else
{
if(count==1)
{ 
//sprintf(output_array,"%c", current_char);             
printf("%c", current_char);
fprintf(outputfile,"%c", current_char);
fprintf(processing,"%c", current_char);

G++;
}

if(count>=2)
{        
       printf("%c%d", current_char, count);
       fprintf(outputfile,"%c%d", current_char,count);
       fprintf(processing,"%c", current_char );
       }

if (count>9)
{
           j++;
           }
           if (count>99)
{
           t++;
           }

//REST ALL COUNT FOR THE SECOND DIFFRENT CHAR IN ARRAY

   current_char = arr[i]; 
   count = 1;
   char_size++;


//BREAK THE LOOP WHEN CHAR IN ARRAY IS NULL       
   if( current_char == '\0' )
   {

           break;

           }   
    } 
    }

 original_length = strlen(arr);
 com_number_length=(char_size+j+t-G);
 compressed_length=(char_size+char_size+j+t-G);

 fclose(outputfile);
 fclose(processing);

 //CALLING FUNCTION-SIZE-CALCULATOR
size_calculator(original_length,char_size,com_number_length,compressed_length);


           }

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