php scandir产生额外的元素(2个点) [英] php scandir produces extra elements (2 dots)

问题描述

我在名为content的目录中有以下文件:仅index.php，page1.php，page2.php和page3.php.

I have the following files in a directory called content: index.php, page1.php, page2.php and page3.php ONLY.

然后我有以下代码:

 $column = scandir("content");
 foreach ($column as $value) {   
  $stvalue = str_replace(".php", "", $value);    
  echo "<div>$stvalue</div>";
}

尽管如此，这是我得到的:

Nevertheless, this is what I get:

<div>.</div>
<div>..</div>
<div>index</div>
<div>page1</div>
<div>page2</div>
<div>page3</div>

前两个元素是什么?我没有这样命名的文件，所以我不知道.

Whats with the first 2 elements? I dont have files named like that so I dont get it.

谢谢.

推荐答案

. -是引用当前目录的特殊目录.

. - is a special directory referencing the current directory.

..-也是一个特殊目录，它引用父目录.

.. - is also a special directory and its referencing the parent directory.

要删除特殊目录，我可以想到一些选项:

To remove the special directories I can think of some options:

1.

foreach(glob("*.php") as $filename) {
    echo "<div>$filename</div>";
}

2.

$files = array_diff(scandir("content"), array('..', '.'));
foreach($files as $file) { ... }

3.

foreach ($files as $file) {    
    if($file != '.' and $file != '..') { ... } 
}

以上所有都是替代方案.如果使用glob()，则无需使用scandir()，反之亦然. glob()-需要一个模式.也可以为它提供这样的路径:
glob("[path]/*.php")-这将列出路径中的所有php文件. glob()文档可在此处找到 PHP-glob()

All of the above are alternatives. You don't need to use scandir() if you use glob() and vice versa. glob() - expects a pattern. It is possible to also provide it with the path like this:
glob("[path]/*.php") - this will list any php file located in path. glob() documentation can be found here PHP - glob()

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