如何在xPath中检查类型是否等于类型或从类型派生 [英] How to check in xPath if a type is equal to a type or derived from the type

问题描述

我正在Schematron中使用xPath.我能够检查类型是否等于目标类型.例如，"xsd:string eq xsd:string".

I'm working with xPath inside Schematron. I'm able to check that a type is equal to a target type. For example 'xsd:string eq xsd:string'.

<sch:rule context="uis:variable/uis:dependency/uis:length">
<sch:assert test="**../../@type eq 'xsd:string'**">      
Text        
</sch:assert>                       
</sch:rule>

我如何检查用户定义的类型是否源自xsd:string?我已经尝试过:

How can I check if a type defined by the user, which has been derived from xsd:string? I've tried:

<sch:rule context="uis:variable/uis:dependency/uis:length">
<sch:assert test="**../../@type instance of attribute (*,xsd:string)**">
Text        
</sch:assert>                       
</sch:rule>

但这不起作用.

推荐答案

没有公开的XPath 2.0功能.实际上，XPath 2.0类型不是一流的值.无法从仅在运行时知道的名称中查找类型，也无法要求类型的属性.您将需要使用扩展:Xerces和Saxon都具有用于询问架构组件的API，并且可以构造调用这些组件的Java扩展函数.

There's no exposed XPath 2.0 functionality for doing this. In fact XPath 2.0 types aren't first-class values; there is no way of finding a type from a name known only at run-time, or asking for properties of the type. You'll need to use extensions: both Xerces and Saxon have APIs for interrogating schema components, and you could construct Java extension functions that invoke these.

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