带select的异步套接字-Python [英] Asynchronous sockets with select - Python

问题描述

我现在正在研究异步套接字，并且我有以下代码:

i am studying asynchronous sockets right now and i have this code:

#!/usr/bin/env python 

""" 
An echo server that uses select to handle multiple clients at a time. 
Entering any line of input at the terminal will exit the server. 
""" 

import select 
import socket 
import sys 

host = 'localhost' 
port = 900 
backlog = 5 
size = 1024 
server = socket.socket(socket.AF_INET, socket.SOCK_STREAM) 
server.bind((host,port)) 
server.listen(backlog) 
input = [server,sys.stdin] 
running = 1 
while running: 
    inputready,outputready,exceptready = select.select(input,[],[]) 

    for s in inputready: 

        if s == server: 
            # handle the server socket 
            client, address = server.accept() 
            input.append(client) 

        elif s == sys.stdin: 
            # handle standard input 
            junk = sys.stdin.readline() 
            running = 0 

        else: 
            # handle all other sockets 
            data = s.recv(size) 
            if data: 
                s.send(data) 
            else: 
                s.close() 
                input.remove(s) 
server.close()

它应该是使用select()的一种基本的回显服务器，但是当我运行它时，我会选择错误10038-尝试使用非套接字的东西进行操作.有人可以告诉我怎么了吗?谢谢:)

It shoud be a basic kind of echo server using select(), but when I run it, I ger select error 10038 - attemp to manipulation with something which is not socket. Can someone tell me what is wrong? Thank you:)

推荐答案

您在Windows上工作，不是吗?在Windows上，select仅在套接字上起作用.但是sys.stdin没有套接字.从第15行中删除它，它应该可以工作.

You are working on Windows, aren't you? On Windows select works only on sockets. But sys.stdin is no socket. Remove it from line 15 and it should work.

在Linux或类似系统上，我希望它能像上面列出的那样工作.

On Linux or the like I would expect it working as listed above.

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