如何根据链接表输出rowName? [英] how do I output the rowName based on a linking table?

问题描述

我需要输出A_Name，B_Name和C_Name.来自tableA，tableB，tableC.我有一个包含上述所有ID的链接表，例如:

I need to output A_Name, B_Name, and C_Name. from tableA, tableB, tableC. I have a linking table containing all the ID's of the above, e.g:

CREATE TABLE `tableLink` (
   `tableLinkID` int(5) NOT NULL auto_increment,
   `A_ID` int(11) NOT NULL,
   `B_ID` int(5) NOT NULL,
   `C_ID` int(5) NOT NULL,
   PRIMARY KEY  (`tableLinkID`)
) ENGINE=InnoDB AUTO_INCREMENT=17 DEFAULT CHARSET=utf8 AUTO_INCREMENT=17 ;

我的问题:我需要了解如何基于具有 C_ID 的选择，如何选择和输出A_ID的[A_Name]，B_ID的[B_Name]和C_ID的[C_Name].

My question: I need to know how to SELECT based on having C_ID, how to select and output A_ID's [A_Name], B_ID's [B_Name], and C_ID's [C_Name].

我希望这很清楚.

(我在变量中有 C_ID )

推荐答案

尝试使用JOIN:

SELECT
    tableA.A_Name,
    tableB.B_Name,
    tableC.C_Name
FROM tableLink
JOIN tableA ON tableLink.A_ID = A.ID
JOIN tableB ON tableLink.B_ID = B.ID
JOIN tableC ON tableLink.C_ID = C.ID
WHERE tableLink.C_ID = 42

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