xslt根据其孙节点的属性值选择祖父母节点 [英] xslt select grandparent node depending on an attribute value of its grandchild node

问题描述

我试图根据其孙节点的属性值向节点添加不同的标签.

I'm trying to add different tags to a node depending on an attribute value of its grandchild node.

样本输入(1x3表格):

Sample Input (a 1x3 table):

<table>
    <row>
        <cell row="1" column="1" >heading text one</cell>
    </row>

    <row>
        <cell row="2" column="1" >body text one</cell>
    </row>
    <row>
        <cell row="3" column="1" >body text two</cell>
    </row>
</table>

需要这样的输出:

<TableElmt>
    <HeadingElmt>
        <RowElmt>
            <CellElmt>heading text one</CellElmt>
        </RowElmt>
    </HeadingElmt>

    <BodyElmt>
        <RowElmt>
            <CellElmt>body text one</CellElmt>
        </RowElmt>
        <RowElmt>
            <CellElmt>body text two</CellElmt>
        </RowElmt>
    </BodyElmt>
</TableElmt>

基本上，我只能基于单元格的@row元素确定行是否为标题行.

Basically I can only decide if the row is a heading row based on the @row element of the cell.

这是我尝试过的:

<xsl:template name="matcheverything" match="table">
    <xsl:apply-templates select="row" />
</xsl:template>

<xsl:template name="matchheadings" match="table[*/*/@row=1]">
    <BodyElmt>
        <xsl:apply-templates select="row" />
    </BodyElmt>
</xsl:template>

<xsl:template match="row">
    <xsl:choose>
        <xsl:when test="*/@row=1">
            <HeadingElmt><RowElmt>
                <xsl:apply-templates select="cell"/>
            </RowElmt></HeadingElmt>
        </xsl:when>
        <xsl:otherwise>
            <RowElmt>
                <xsl:apply-templates select="cell"/>
            </RowElmt>
        </xsl:otherwise>
    </xsl:choose>
</xsl:template>

<xsl:template match="cell">
    <CellElmt><xsl:apply-templates select="*"/></CellElmt>
</xsl:template>

我当时认为具有更具体匹配要求的"matchheadings"模板应该识别标题行，但是实际上它匹配表中的每一行.

I was thinking the "matchheadings" template, having a more specific match requirement, should recognize the heading row, however it's actually matching every single row in the table.

因此，我从此样式表实际输出的结果是将每一行都视为标题行-非常糟糕:(

So my actual out put from this stylesheet is every row treated as a heading row - very bad :(

<TableElmt>
    <HeadingElmt>
        <RowElmt>
            <CellElmt>heading text one</CellElmt>
        </RowElmt>

        <RowElmt>
            <CellElmt>body text one</CellElmt>
        </RowElmt>
        <RowElmt>
            <CellElmt>body text two</CellElmt>
        </RowElmt>
    </HeadingElmt>
</TableElmt>

推荐答案

此转换:

<xsl:stylesheet version="1.0"
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 <xsl:output omit-xml-declaration="yes" indent="yes"/>
 <xsl:strip-space elements="*"/>

 <xsl:template match="table">
  <TableElmt>
   <xsl:apply-templates/>
  </TableElmt>
 </xsl:template>

 <xsl:template match="row[cell/@row='1']">
  <HeadingElmt>
   <xsl:apply-templates select="." mode="copy"/>
  </HeadingElmt>
 </xsl:template>

 <xsl:template match="row[cell[not(@row='1')]][1]">
  <BodyElmt>
   <xsl:apply-templates select=".|following-sibling::row" mode="copy"/>
  </BodyElmt>
 </xsl:template>

 <xsl:template match="row" mode="copy">
   <RowElmt>
     <xsl:apply-templates/>
   </RowElmt>
 </xsl:template>

 <xsl:template match="cell">
   <CellElmt>
    <xsl:value-of select="."/>
   </CellElmt>
 </xsl:template>

 <xsl:template match="row"/>
</xsl:stylesheet>

应用于提供的XML文档:

<table>
    <row>
        <cell row="1" column="1" >heading text one</cell>
    </row>
    <row>
        <cell row="2" column="1" >body text one</cell>
    </row>
    <row>
        <cell row="3" column="1" >body text two</cell>
    </row>
</table>

产生想要的正确结果:

<TableElmt>
    <HeadingElmt>
        <RowElmt>
            <CellElmt>heading text one</CellElmt>
        </RowElmt>
    </HeadingElmt>
    <BodyElmt>
        <RowElmt>
            <CellElmt>body text one</CellElmt>
        </RowElmt>
        <RowElmt>
            <CellElmt>body text two</CellElmt>
        </RowElmt>
    </BodyElmt>
</TableElmt>

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