MYSQL选择子查询IF是否存在 [英] MYSQL Select Subquery IF exists

问题描述

我有3张桌子....用户，更新和撞车.

I have 3 tables ....users, updates and bumps.

我想返回使api请求供稿的用户以最新顺序更新供稿，其中包含所有必需的数据，以显示供稿中的每个状态. 我还需要包括该更新是否已由发出api请求的用户碰撞"(碰撞=喜欢在Facebook上的状态)

I want to return the user making the api request a feed updates in most recent order with all the needed data to display each of the statuses in the feed. I also need to include whether the update has been "bumped" by the user making the api request or not (bumped = liking a status on facebook)

简而言之，即使此查询的if计数区域中没有正确语法附近的地方，这也是我要尝试的操作:

In a nutshell this is what I am trying to do even though the if count area of this query is no where near correct syntax:

SELECT b.type,b.owner,b.update_img,b.ALBUM_ID,b.last_comment,a.uid, a.first_name, a.last_name, a.gender, a.thumb_img, b.msg_id, b.message, b.created,b.POST_PRIVACY,
(if count( SELECT  * FROM BUMPS WHERE  b.msg_id= BUMPS.MSG_ID_FK  AND BUMPS.UID_FK=$loggedin_uid)>0  THEN  1  ELSE  null)  as 'isBumpedBool'
FROM users AS a, updates AS b
WHERE b.uid_fk = a.uid
AND b.type<>'FRIEND_RELATIONSHIP'
AND b.created<$time
AND b.type<>'FAMILIAR_RELATIONSHIP'
AND a.college='$college'
AND b.POST_PRIVACY<>'4'
AND b.POST_PRIVACY<>'5'
AND b.created>=$tstamp
ORDER BY b.created DESC
LIMIT 100

有什么想法吗?

推荐答案

添加一个LEFT JOIN以将所有这些结果JOINed到BUMPS上，如果值不存在则返回NULL

Add a LEFT JOIN to get all those result JOINed to BUMPS and return NULLs if the values are not there

SELECT b.type,
       b.owner,
       b.update_img,
       b.ALBUM_ID,
       b.last_comment,
       a.uid,
       a.first_name,
       a.last_name,
       a.gender,
       a.thumb_img,
       b.msg_id,
       b.message,
       b.created,
       b.POST_PRIVACY,
       (CASE WHEN bm.MSG_ID_FK IS NOT NULL THEN 1 ELSE NULL END) AS 'isBumpedBool'
FROM users AS a JOIN
     updates AS b
ON b.uid_fk = a.uid
  AND b.type<>'FRIEND_RELATIONSHIP'
  AND b.created<$time
  AND b.type<>'FAMILIAR_RELATIONSHIP'
  AND a.college='$college'
  AND b.POST_PRIVACY<>'4'
  AND b.POST_PRIVACY<>'5'
  AND b.created>=$tstamp
LEFT JOIN BUMPS as bm 
ON b.msg_id= bm.MSG_ID_FK
             AND bm.UID_FK=$loggedin_uid
ORDER BY b.created DESC LIMIT 100

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