用户编辑任何表单时如何显示所选的下拉值? [英] how to display selected dropdown value when user edit any form?

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问题描述

我创建了州和城市的依赖下拉列表.是财产申报书.用户编辑表单时,我想显示所选的州和城市.我设法以某种方式显示选定的状态.我写了get_city函数function.php并通过ajax调用它,我有两个不同的表,即州和城市.所以问题是我不明白如何显示所选城市? 这是我的下拉代码

I have created dependent drop down of state and city. It is property submission form. When user edit the form, I want to display selected state and city. I managed to display selected state somehow. I have written get_city function function.php and call it through ajax.I have two different tables i.e. state and city. So problem is I dont understand how to show selected city?? This is my code for drop down

<select name="state" id="state" class="select-submit2">
   <option value="">Select state</option>

   <?php 
   $property_id = $_GET['listing_edit']; 
   $property_state = get_post_meta($property_id, state, true);
   $result=$wpdb->get_results("select * from states");
   //$wpdb->get_results($query);
   foreach($result as $row) {
      $state_id=$row->state_id;
      $state_name=$row->state_name;     
?>
<option value="<?php echo $state_id; ?>" <?php if($property_state == $state_id){ echo 
 'selected="selected"';} ?>><?php echo $state_name; ?></option>
<?php 
      //echo '<option value='.$state_id.'>'.$state_name.'</option>';
   }
?>          
</select>
<input type="hidden" name="edit_id" id="edit_id" value="<?php echo $edit_id;?>">
<select name="district" id="district" required class="select-submit2">
   <option value="">Select District</option>
</select> 

在上面的代码中,我正在显示选定状态.我在Google上进行搜索,发现我必须将post ID传递给function.php中的函数.这是我对function.php文件中的get_city函数的代码

In the above code i am displaying selected state. I searched on google and found that I have to pass post id to function in function.php. This is my code for get_city function in function.php file

function getcity() {

global $wpdb;

   if($_POST['state']) {
      $id = $_POST['state'];
      global $edit_id;
      $property_id = $edit_id; 
      $district = get_post_meta($property_id, 'district', true);
      $result=$wpdb->get_results("SELECT * FROM districts WHERE state_id='$id'");

      foreach($result as $row) {
         $city_name = $row->district_name;
         $city_id = $row->district_id;
?>
<option value="<?php echo $city_id; ?>" <?php if($district == $city_id){ echo 'selected="selected"';} ?>><?php echo $city_name; ?></option>
<?php    
         //echo '<option value="'.$city_id.'">'.$city_name.'</option>';                 
      }
   }
}
add_action("wp_ajax_nopriv_getcity", "getcity");
add_action("wp_ajax_getcity", "getcity");

这是我的js代码...

This is my js code...

 jQuery(document).ready(function($) {

  $('#state').on('change', function() {

   var state  = $('#state').val();
   var edit_id = $('#edit_id').val();

   $.ajax
   ({
    type : "POST",
    url  : "http://whitecode.in/demo/plotsup_plot/wp-admin/admin-ajax.php",
    data :{'action' : 'getcity', 'state' : state , 'edit_id' : edit_id },
    success: function(html) {

      $("#district").removeAttr("disabled");
      $("#district").html(html);
     }

    });
   });

 <input type="hidden" name="edit_id" id="edit_id" value="<?php echo $edit_id;?>">

推荐答案

尝试一下,让我知道它是否有效.在全局$ edit_id的两行中进行了更改;已删除,并且$ property_id行已更改.请正确应用更改,让我知道是否可以.

Try this and let me know if it works or not. The change is made on two lines global $edit_id; has been removed and the $property_id line has been changes. Please apply the changes properly and let me know if they are ok.

<?php
function getcity() {

global $wpdb;

if($_POST['state']) {
  $id = $_POST['state'];
  $property_id = $_POST['edit_id']; 
  $district = get_post_meta($property_id, 'district', true);
  $result=$wpdb->get_results("SELECT * FROM districts WHERE state_id='$id'");

  foreach($result as $row) {
     $city_name = $row->district_name;
     $city_id = $row->district_id;
 ?>
<option value="<?php echo $city_id; ?>" <?php if($district == $city_id){ echo 'selected="selected"';} ?>><?php echo $city_name; ?></option>
<?php    
     //echo '<option value="'.$city_id.'">'.$city_name.'</option>';                 
  }
}
}
add_action("wp_ajax_nopriv_getcity", "getcity");
add_action("wp_ajax_getcity", "getcity");

这篇关于用户编辑任何表单时如何显示所选的下拉值?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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