SQL SELECT WHERE行包含单词 [英] SQL SELECT WHERE row contains word

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问题描述

我需要从包含单词limit 1的行中进行选择,并将其回显.

i need to select from row where contains word limit 1, and echo it out.

例如,我在行类别中的名称大于1000 cars,而200具有相同的名称,我只想从每辆汽车中选择一个.

So for example, i have in row categories more than 1000 cars which 200 with the same name, i only want to select from each car only one.

SELECT * FROM brands
WHERE car (bmw,audi,mercedes )

并按最新添加的内容排序

And sort by newest added

推荐答案

无重复

您要DISTINCT或GROUP BY mysql语句:

No duplicates

You want to DISTINCT or GROUP BY mysql statement:

  • DISTINCT: http://www.w3schools.com/sql/sql_distinct.asp
  • GROUP BY: http://www.w3schools.com/sql/sql_groupby.asp

声明:

SELECT DISTINCT(name) FROM cars

SELECT name FROM cars GROUP BY name

不返回重复的名称

如其他答案所示,您可以使用WHERE IN过滤一组数据:

As shown in other answers you can use WHERE IN to filter on an set of data:

WHERE `column` IN ('item`1', 'item2', ..) 

您还可以使用它来子查询:

you can also use this to subquery:

SELECT * FROM cars WHERE brandId IN (SELECT Id FROM brands WHERE name IN ('BMW', 'Volkwagen', ..)

参考: http://www.w3schools.com/sql/sql_in.asp

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