单发:带有参数的SLOT [英] Singleshot: SLOT with arguments

问题描述

我有一个奇怪的问题.这是我的代码:

I have a strange problem. Here is my code:

def method1(self, arg1, delay=True):
    """This is a method class"""

    def recall(arg1):
        self.method1(arg1, delay=False)
        return

    if delay:
            print "A: ", arg1, type(arg1)
            QtCore.QTimer.singleShot(1, self, QtCore.SLOT(recall(int)), arg1)
            return

    print "B: ", arg1, type(arg1)

所以我可以在控制台中找到它:

So I get this in console:

A:  0 <type 'int'>
B:  <type 'int'> <type 'type'>

在"B"中，您应获得与在"A"中相同的结果.有人知道怎么了吗?我如何获得arg1值 而不是它的类型?这没有任何意义...

In "B" you should get the same than in "A". Anyone knows what's wrong? How can I get the arg1 value instead of its type? This is not making any sense...

PS:我正在尝试这样的事情: http://lists.trolltech.com/qt-interest/2004-08/thread00659-0.html

PS: I'm trying something like this: http://lists.trolltech.com/qt-interest/2004-08/thread00659-0.html

推荐答案

调用时看起来像这样:

QtCore.QTimer.singleShot(1, self, QtCore.SLOT(recall(int)), arg1)

您是要打电话给它吗?

QtCore.QTimer.singleShot(1, self, QtCore.SLOT(recall(arg1)), arg1)

您将int作为recall的第一个参数传递，它直接将其传递给method1. int是类型对象(整数类型).

you are passing int as the first argument of recall, which passes it directly to method1. int is a type object (the type of integers).

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