获取断开连接事件时客户端当前所在的房间的列表 [英] Get the list of rooms the client is currently in on disconnect event

问题描述

我正在尝试查找断开连接事件(关闭浏览器/重新加载页面/断开互联网连接)时客户端当前所在的房间的列表.

I am trying to find the list of rooms a client is currently in on disconnect event (closes the browsers / reloading the page / internet connection was dropped).

由于以下原因，我需要它:用户进入了几个房间.然后其他人也做了同样的事情.然后，他关闭浏览器选项卡.我想通知所有房间里的人他离开了.

I need it for the following reason: user has entered few rooms. Then other people has done the same. Then he closes a browser tab. And I want to notify all the people in the rooms he is in that he left.

所以我需要在'disconnect'事件中做一些事情.

So I need to do something inside of on 'disconnect' event.

io.sockets.on('connection', function(client){
  ...
  client.on('disconnect', function(){

  });
});

---

我已经尝试了两种方法，发现它们都是错误的:

---

I already tried two approaches and found that both of them are wrong:

1)遍历adapter.rooms.

for (room in client.adapter.rooms){
   io.sockets.in(room).emit('userDisconnected', UID);
 }

这是错误的，因为适配器房间拥有所有房间.不仅我的客户所在的房间.

This is wrong, because adapter rooms has all rooms. Not only the rooms my client is in.

2)正在经历client.rooms.这将返回客户端所在房间的正确列表，但不会返回断开连接事件.在断开连接时，该列表已经为空[].

2) Going through client.rooms. This returns a correct list of rooms the client is in, but no on the disconnect event. On disconnect this list is already empty [].

那我该怎么办呢?我在撰写本文时正在使用最新的socket.io: 1.1.0

So how can I do it? I am using the latest socket.io at the time of writing: 1.1.0

推荐答案

默认情况下这是不可能的.看一下socket.io的源代码.

This is not possible by default. Have a look at the source code of socket.io.

您有方法Socket.prototype.onclose，该方法在socket.on('disconnect',..)回调之前执行.因此，所有房间都在此之前保留.

There you have the method Socket.prototype.onclose which is executed before the socket.on('disconnect',..) callback. So all rooms are left before that.

/**
 * Called upon closing. Called by `Client`.
 *
 * @param {String} reason
 * @api private
 */

Socket.prototype.onclose = function(reason){
  if (!this.connected) return this;
  debug('closing socket - reason %s', reason);
  this.leaveAll();
  this.nsp.remove(this);
  this.client.remove(this);
  this.connected = false;
  this.disconnected = true;
  delete this.nsp.connected[this.id];
  this.emit('disconnect', reason);
};

一种解决方案 可以是破解socket.js库代码或覆盖此方法，然后调用原始方法.我对它似乎有效地进行了快速测试:

A solution could be either to hack the socket.js library code or to overwrite this method and then call the original one. I tested it pretty quick at it seems to work:

socket.onclose = function(reason){
    //emit to rooms here
    //acceess socket.adapter.sids[socket.id] to get all rooms for the socket
    console.log(socket.adapter.sids[socket.id]);
    Object.getPrototypeOf(this).onclose.call(this,reason);
}

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