批处理:从具有冒号和感叹号的文件中读取一行 [英] Batch: Reading in a line from a file that has a colon and exclamation

问题描述

我正在尝试从包含冒号和感叹号的文件中读取一行.当我回显那条线时，它仅显示结肠之后的所有内容.我需要保留enabledelayedexpansion以获取将在do循环中执行的更高级的代码.但是现在我只想正确地回声. 任何帮助将不胜感激！

I'm trying to read in a line from a file that contains a colon and exclamation point. When I echo that line, it only shows everything AFTER the colon. I need to keep the enabledelayedexpansion for more advanced code I will be doing in the do loop. But right now I just want to echo properly. Any help would be appreciated!

文件将显示以下内容:

！ 12345 APX: 6.32

! 12345 APX: 6.32

我尝试的代码是:

setlocal EnableDelayedExpansion
cd C:\Users\jwagh\Desktop\
for /f "usebackq delims=" %%a in (test.txt) DO (
setlocal DisableDelayedExpansion
 echo %%a
 set line=%%a
 set example=%line:~0,-1%
 echo %example%
)

推荐答案

可能仅禁用延迟扩展是唯一可行的解​​决方案，但是根据您的数据，将delims设置为!会将%%a设置为整行，减去开头的!(显然仅假设一个已知长度的!序列，并且总是在该行的前面)

Probably disabling delayedexpansion is the only practicable solution, but depending on your data, setting delims to ! would set %%a to the entire line, minus the initial ! (assuming obviously only one !-sequence of known length and it always leads the line)

OR

for /f "usebackq delims=!" %%a in (%FamilyFile%) DO echo ^^!%%a

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