如何按给定索引的项目过滤元组列表并将其转换为列表字典 [英] How to filter a list of tuples by items at given index and convert them into a dictionary of lists

问题描述

我有一个如下列表:

Lista = [('amazon', 'Amazon', 1.0), 
         ('amazon', 'Alexa', 0.8), 
         ('amazon', 'microsoft', 0.6), 
         ('amazon', 'Amazon Pay', 0.7), 
         ('amazon', 'Prime', 0.4),
         ('alien', 'jack' , 0.0), 
         ('alien', 'dell', 0.6),
         ('alien', 'apple', 0.0),
         ('alien', 'orange', 0.0),
         ('alien', 'fig', 0.0)]

现在，我要执行基本检查，以查看哪些元组的最后一个值大于0.0，然后将所得的元组转换为列表的字典:

Now I want to perform a basic check to see which tuples have the last value greater than 0.0 and then convert the resulting tuples into a dict of lists:

new_words = {'amazon': ['Amazon', 'Alexa', 'microsoft', 'Amazon Pay', 'Prime'],
             'alien': ['dell']}

我该怎么办?

推荐答案

您无法在字典中获得所需的结果，因为字典中不包含重复的键(类似于普通的英语词典:其中的单词可能拼写相同，但发音有所不同.

You can't have the desired result in a dictionary as dictionaries don't contain duplicate keys (similar to a normal English dictionary: where the words might spell the same but there are differences in pronunciation).

所需结果可以再次存储到列表中.

The desired result can be stored again into a list.

newDict = {}
result = []

Lista =[('amazon', 'Amazon', 1.0), ('amazon', 'Alexa', 0.8), ('amazon', 'microsoft', 0.6), ('amazon', 'Amazon Pay', 0.7), ('amazon', 'Prime', 0.4),('alien', 'jack' , 0.0), ('alien', 'dell', 0.6), ('alien', 'apple', 0.0), ('alien', 'orange', 0.0), ('alien', 'fig', 0.0)]

for items in Lista:
    if items[2] > 0.0:
        newDict[items[0]] = items[1]
        result.append(newDict)
        newDict = {}

print result

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