包含至少1个数字和1个字符且固定长度为11的字母数字字符串的正则表达式 [英] Regex for alphanumeric string with at least 1 number and 1 character and a fixed length of 11

问题描述

我需要正则表达式来匹配长度为11个字符的字母数字字符串，但该值必须至少包含1个字符和1个数字.

I need regex to match an alphanumeric string exact 11 characters long but the value must contain at least both 1 character and 1 number.

结合使用 至少包含字母数字的正则表达式1个数字和1个字符

即/^(?=.*[0-9])(?=.*[a-zA-Z])([a-zA-Z0-9]+)$/

和什么是正则表达式以匹配字母数字6字符串?

即^[a-zA-Z0-9]{6,}$

通过使用像这样的OR(||)运算符

by using OR (||) operator like this

//regex code
var str = "";
if ($.trim($("input[id$='txtBranchName']").val()) != "")
    str = $.trim($("input[id$='txtBranchName']").val());
var reg_exp = /^(?:[0-9]+[a-z]|[a-z]+[0-9])[a-z0-9]*$/i; // /^[a-zA-Z0-9]{11,}$/;//^(\d)(?:\1+)?$/; // new RegExp('([0-9]){6}');
var reg_exp2 = /^[a-zA-Z0-9]{11,11}$/;
if (!reg_exp.test(str) || !reg_exp2.test(str)) {
    $("span[id$='lblError']").css("color", "red");
    $("span[id$='lblError']").html($("span[id$='lbl_PayeeInformation_IFSCNo']").html()).show();
    $("input[id$='txtBranchName']").focus();
    returned = false;
    return false;
}
//end regex code

但是如果我用一个正则表达式得到它，那就太好了.

but it would be great if i get it in one regex.

推荐答案

您需要将两者结合起来并使用 {11} 精确匹配11个字符.

You need to combine both and use {11} for exact 11 characters match.

/^(?=.*\d)(?=.*[a-zA-Z])[a-zA-Z0-9]{11}$/

---

位置:

---

Where :

1. (?=.*\d)断言该位置在任何位置(其中\d等同于[0-9])都在数字后面.
2. (?=.*[a-zA-Z])断言该位置在任何位置都跟随字母.
3. [a-zA-Z0-9]{11}仅在长度为11个字符且在字符类内时匹配.
4. ^和$ 是开始和结束锚点，有助于检查整个字符串.

1. (?=.*\d) assert that the position follows a digit at any position(where \d is equivalent to [0-9]).
2. (?=.*[a-zA-Z]) assert that the position follows an alphabet at any position.
3. [a-zA-Z0-9]{11} matches only when the length is 11 characters and within the character class.
4. ^ and $ are start and end anchors which help to check whole string.

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