将尝试/最后（不捕捉）泡沫的例外呢？ [英] Will Try / Finally (without the Catch) bubble the exception?

问题描述

我几乎可以肯定的是，答案是肯定的。如果我使用try Finally块，但不使用Catch块则任何异常都将泡沫。是否正确？

I am almost positive that the answer is YES. If I use a Try Finally block but do not use a Catch block then any exceptions WILL bubble. Correct?

在一般的做法有什么想法？

Any thoughts on the practice in general?

赛斯

推荐答案

是的，绝对不会。假设你的最后块不抛出异常，当然，在这种情况下，这将有效地取代一个最初抛出。

Yes, it absolutely will. Assuming your finally block doesn't throw an exception, of course, in which case that will effectively "replace" the one that was originally thrown.

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