按多个属性对列表进行排序? [英] Sort a list by multiple attributes?

问题描述

我有一个列表列表:

[[12, 'tall', 'blue', 1],
[2, 'short', 'red', 9],
[4, 'tall', 'blue', 13]]

如果我想按一个元素(例如，高/短元素)进行排序，则可以通过s = sorted(s, key = itemgetter(1))进行.

If I wanted to sort by one element, say the tall/short element, I could do it via s = sorted(s, key = itemgetter(1)).

如果我想按长/短和颜色同时进行排序，我可以进行两次排序，每个元素一次，但是有一种更快的方法吗?

If I wanted to sort by both tall/short and colour, I could do the sort twice, once for each element, but is there a quicker way?

推荐答案

键可以是返回元组的函数:

A key can be a function that returns a tuple:

s = sorted(s, key = lambda x: (x[1], x[2]))

或者您可以使用itemgetter来实现相同目的(更快，并且避免了Python函数调用):

Or you can achieve the same using itemgetter (which is faster and avoids a Python function call):

import operator
s = sorted(s, key = operator.itemgetter(1, 2))

请注意，在这里您可以使用sort而不是sorted然后重新分配:

And notice that here you can use sort instead of using sorted and then reassigning:

s.sort(key = operator.itemgetter(1, 2))

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