Swift用字符串和数字对数组进行排序 [英] Swift sort an array with strings and numbers

问题描述

我有一个字符串数组，

let array = [ "10", "1", "101", "NA", "100", "20", "210", "200", "NA", "7" ]

我想将输出升序排列，

let sorted = [ "1", "7", "10", "20", "100", "101", "200", "210", "NA", "NA" ]

我尝试使用sorted命令，但是遇到超过2位数字(例如:100、101、200等)时，该命令不起作用

I tried using the sorted command but it does not work when it encounters more than 2 digits e.g.: 100, 101, 200 etc.

array.sorted { $0? < $1? }

简单的方法是什么?

推荐答案

编辑/更新: Xcode 10.2.x•Swift 5

您可以使用String方法localizedStandardCompare

You can use String method localizedStandardCompare

let array = [ "10", "1", "101", "NA", "100", "20", "210", "200", "NA", "7" ]
let sorted = array.sorted {$0.localizedStandardCompare($1) == .orderedAscending}

print(sorted) // ["1", "7", "10", "20", "100", "101", "200", "210", "NA", "NA"]

---

或在MutableCollection上使用方法sort(by:):

var array = [ "10", "1", "101", "NA", "100", "20", "210", "200", "NA", "7" ]
array.sort {$0.localizedStandardCompare($1) == .orderedAscending}

print(array) // ["1", "7", "10", "20", "100", "101", "200", "210", "NA", "NA"]

---

您还可以实现扩展Collection的自己的本地化标准排序方法:

---

You can also implement your own localized standard sort method extending Collection:

extension Collection where Element: StringProtocol {
    public func localizedStandardSorted(_ result: ComparisonResult) -> [Element] {
        return sorted { $0.localizedStandardCompare($1) == result }
    }
}

---

let array = [ "10", "1", "101", "NA", "100", "20", "210", "200", "NA", "7" ]
let sorted = array.localizedStandardSorted(.orderedAscending)

print(sorted) // ["1", "7", "10", "20", "100", "101", "200", "210", "NA", "NA"]

---

变异方法以及对MutableCollection的扩展:

---

The mutating method as well extending MutableCollection:

extension MutableCollection where Element: StringProtocol, Self: RandomAccessCollection {
    public mutating func localizedStandardSort(_ result: ComparisonResult) {
        sort { $0.localizedStandardCompare($1) == result }
    }
}

---

var array = [ "10", "1", "101", "NA", "100", "20", "210", "200", "NA", "7" ]
array.localizedStandardSort(.orderedAscending)

print(array) // ["1", "7", "10", "20", "100", "101", "200", "210", "NA", "NA"]

如果需要对数组进行数字排序，则可以使用字符串比较方法，将options参数设置为.numeric:

If you need to sort your array numerically you can use String compare method setting the options parameter to .numeric:

public extension Collection where Element: StringProtocol {
    func sortedNumerically(_ result: ComparisonResult) -> [Element] {
        return sorted { $0.compare($1, options: .numeric) == result }
    }
}
public extension MutableCollection where Element: StringProtocol, Self: RandomAccessCollection {
    mutating func sortNumerically(_ result: ComparisonResult) {
        sort { $0.compare($1, options: .numeric) == result }
    }
}

---

var numbers = ["1.5","0.5","1"]
let sorted = numbers.sortedNumerically(.orderedAscending)
print(sorted)  // ["0.5", "1", "1.5"]
print(numbers) // ["1.5","0.5","1"]
// mutating the original collection
numbers.sortNumerically(.orderedDescending)
print(numbers)  // "["1.5", "1", "0.5"]\n"

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