Python按元组中值的长度对列表进行排序 [英] Python sort a List by length of value in tuple

问题描述

我在排序元组列表时遇到困难.我想按列表中字符串的长度排序.

I am having difficulty sorting a list of tuples. I would like to sort by the length of a string in the list.

例如:

l = [(99,'bbc', 121),(33,'abcd', 231),(44,'zb', 148), (23,'abcde',221)]

如果我按元素1排序:

l.sort(key=itemgetter(1), reverse=True)

这将根据字符串的字母顺序(而不是长度)进行排序.我宁愿就地排序和反向排序，以最长的字符串在前.

This will sort on the alphabetical ranking of the strings, not the length. I would prefer to sort in-place and reverse sort, with longest string first.

我可以使用lambda和cmp，

I can use a lambda and cmp,

l.sort(lambda x,y: cmp(len(x[1]), len(y[1])), reverse=True)

但是使用key和/或itemgetter是否有更优雅或更pythonic的方式?

but is there a more elegant, or pythonic way using key and/or itemgetter?

推荐答案

您可以使Lambda更加简单:

Well you can make the lambda simpler:

l.sort(key=lambda t: len(t[1]), reverse=True)

另外，不要使用list作为变量名；它已经被内置函数使用了.

Also, don't use list as a variable name; it's already taken by a built-in function.

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