我可以在Python中按文本的数值对其进行排序吗? [英] Can I sort text by its numeric value in Python?

问题描述

我在Python中使用以下形式的键来表示字典:

I have dict in Python with keys of the following form:

mydict = {'0'     : 10,
          '1'     : 23,
          '2.0'   : 321,
          '2.1'   : 3231,
          '3'     : 3,
          '4.0.0' : 1,
          '4.0.1' : 10,
          '5'     : 11,
          # ... etc
          '10'    : 32,
          '11.0'  : 3,
          '11.1'  : 243,
          '12.0'  : 3,
          '12.1.0': 1,
          '12.1.1': 2,
          }

有些索引没有子值，有些索引有一个子级别，有些索引有两个.如果我只有一个子级别，则可以将它们全部视为数字并按数字排序.第二个子级别迫使我将它们全部当作字符串来处理.但是，如果我像字符串一样对它们进行排序，则在1之后将10在2之后具有20.

Some of the indices have no sub-values, some have one level of sub-values and some have two. If I only had one sub-level I could treat them all as numbers and sort numerically. The second sub-level forces me to handle them all as strings. However, if I sort them like strings I'll have 10 following 1 and 20 following 2.

如何正确排序索引?

注意:我真正想做的是打印出按索引排序的字典.如果有比通过某种方式对它进行排序更好的方法，那对我来说很好.

Note: What I really want to do is print out the dict sorted by index. If there's a better way to do it than sorting it somehow that's fine with me.

推荐答案

您可以按所需的方式对键进行排序，方法是将其拆分为'.然后将每个组件转换为整数，如下所示:

You can sort the keys the way that you want, by splitting them on '.' and then converting each of the components into an integer, like this:

sorted(mydict.keys(), key=lambda a:map(int,a.split('.')))

返回以下内容:

['0',
 '1',
 '2.0',
 '2.1',
 '3',
 '4.0.0',
 '4.0.1',
 '5',
 '10',
 '11.0',
 '11.1',
 '12.0',
 '12.1.0',
 '12.1.1']

您可以遍历该键列表，并根据需要将值从字典中拉出.

You can iterate over that list of keys, and pull the values out of your dictionary as needed.

您还可以非常相似地对mydict.items()的结果进行排序:

You could also sort the result of mydict.items(), very similarly:

sorted(mydict.items(), key=lambda a:map(int,a[0].split('.')))

这为您提供了(键，值)对的排序列表，如下所示:

This gives you a sorted list of (key, value) pairs, like this:

[('0', 10),
 ('1', 23),
 ('2.0', 321),
 ('2.1', 3231),
 ('3', 3),
 # ...
 ('12.1.1', 2)]

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