Python，如何对对象列表进行排序? [英] Python, how to sort list of object?

问题描述

我有一个看起来像这样的对象列表.

I have a list of object that looks like this.

hand = [ Card(10, 'H'), Card(2,'h'), Card(12,'h'), Card(13, 'h'), Card(14, 'h') ]

Card(10，'H)在这里不是元组，而是对象.如果列表中的每个项目都是元组形式的，我知道如何对该列表进行排序，

Card(10, 'H) here is not a tuple, but an object. I know how to sort this list if each item in the list was in a form of tuple, like this,

hand = sorted(hand, key = lambda x: x[0])

但是我不知道如何对对象列表进行排序.我想按第一个输入值(即Card()中的数字)对列表进行排序

but I have no idea how to sort a list of objects. I want to sort my list by the first input value, which is the number in Card()

我该怎么做?

这是Card()的定义.

Here's the definition of Card().

class Card(object):

    RANKS = (2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14)

    SUITS = ('C', 'D', 'H', 'S')

    def __init__(self, rank=12, suit='S'):

        if (rank in Card.RANKS):
            self.rank = rank
        else:
            self.rank = 12

        if (suit in Card.SUITS):
            self.suit = suit.upper()
        else:
            self.suit = 'S'

    def __str__(self):
        if (self.rank == 14):
            rank = 'A'
        elif (self.rank == 13):
            rank = 'K'
        elif (self.rank == 12):
            rank = 'Q'
        elif (self.rank == 11):
            rank = 'J'
        else:
            rank = str(self.rank)
        return rank + self.suit

    def __eq__(self, other):
        return (self.rank == other.rank)

    def __ne__(self, other):
        return (self.rank != other.rank)

    def __lt__(self, other):
        return (self.rank < other.rank)

    def __le__(self, other):
        return (self.rank <= other.rank)

    def __gt__(self, other):
        return (self.rank > other.rank)

    def __ge__(self, other):
        return (self.rank >= other.rank)

推荐答案

想法仍然相同.只是您将在类对象中寻找特定的属性.

The idea is still the same. Just that you will be looking for a specific attribute in the class object.

对于您的卡类，您可以执行以下操作:

For your card class, you could do something like this:

hand = [ Card(10, 'H'), Card(2,'h'), Card(12,'h'), Card(13, 'h'), Card(14, 'h') ]

那你可以做

sorted_cards = sorted(hand, key=lambda x: x.rank)

输出看起来像这样:

>>> [card.number for card in sorted_cards]
[2, 10, 12, 13, 14]

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